In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
<span>Let us use the variable x for length. So width will be 1/2x + 3.
Perimeter = x+x+ 1/2x + 3 +1/2x + 3 = 3x + 6 = 66
Therefore 3x = 66-6 = 60
So x = 60/3 = 20
The length is 20 cm.
Therefore the width = 1/2 of 20 + 3 = 10 + 3 = 13 cm
Check: 20+20+13+13 = 66</span>
Answer:
a = b / 6
Step-by-step explanation:
Assuming we want to factor the formula to (x+3)(x+3), you want to have a +9 where there is a -4 now. So you must add 13.
5 packages of spoons and and 4 packages of forks
