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jek_recluse [69]
3 years ago
12

Simplify the following expression: 8x − 8y + 5z − 3x − 14y + 3z

Mathematics
2 answers:
Anon25 [30]3 years ago
4 0

Answer:

5x-22y+8z

Step-by-step explanation:

Given : 8x−8y+5z−3x−14y+3z

To find : which of the following is the answer

a. 11x − 22y + 8z  

b. 5x − 6y + 8z  

c. 5x − 22y + 8z  

d. 11x − 6y + 8z

Solution :

8x-8y+5z-3x-14y+3z

5x-22y+8z

Thus the simplified expression is 5x-22y+8z

Thus option C is correct .

RideAnS [48]3 years ago
3 0
The answer is C. 5x - 22y + 8z
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zheka24 [161]

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tan 45° = 3/x

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5 0
3 years ago
Find the missing side or angle.
bonufazy [111]

Answer:

c = 6.1

Step-by-step explanation:

Given that: B = 18° , C = 152°,  and b = 4.

The missing side, c, can be determined by applying the sine rule which states that:

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{4}{Sin 18^{o} } = \frac{c}{Sin 152^{o} }

c = \frac{4* Sin 152^{o} }{Sin 18^{o} }

 = \frac{1.8779}{0.3090}

 = 6.0773

c = 6.1

Therefore,  the value of the missing side, c, is 6.1

3 0
3 years ago
Joe is saving money for his
tatyana61 [14]

Answer:

He will need to save $295

Step-by-step explanation:

he needs 450 and he has 155, so all you would do is subtract 155 from 450 and you get the rest he needs which is 295

6 0
2 years ago
Suppose a continuous probability distribution has an average of μ=35 and a standard deviation of σ=16. Draw 100 times at random
yulyashka [42]

Answer:

To use a Normal distribution to approximate the chance the sum total will be between 3000 and 4000 (inclusive), we use the area from a lower bound of 3000 to an upper bound of 4000 under a Normal curve with its center (average) at 3500 and a spread (standard deviation) of 160 . The estimated probability is 99.82%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we have that the mean is \mu*n and the standard deviation is s = \sigma \sqrt{n}

In this problem, we have that:

\mu = 100*35 = 3500, \sigma = \sqrt{100}*16 = 160

This probability is the pvalue of Z when X = 4000 subtracted by the pvalue of Z when X = 3000.

X = 4000

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{4000 - 3500}{160}

Z = 3.13

Z = 3.13 has a pvalue of 0.9991

X = 3000

Z = \frac{X - \mu}{s}

Z = \frac{3000 - 3500}{160}

Z = -3.13

Z = -3.13 has a pvalue of 0.0009

0.9991 - 0.0009 = 0.9982

So the correct answer is:

To use a Normal distribution to approximate the chance the sum total will be between 3000 and 4000 (inclusive), we use the area from a lower bound of 3000 to an upper bound of 4000 under a Normal curve with its center (average) at 3500 and a spread (standard deviation) of 160 . The estimated probability is 99.82%.

5 0
3 years ago
Evaluate and answer in standard form:<br><br>4^2/3^2​
Semenov [28]

the answer is : 1.7777

6 0
2 years ago
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