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goldfiish [28.3K]
3 years ago
14

Find the coordinates of the circumcenter of △PQR with vertices P(−2,5), Q(4,1), and R(−2,−3).

Mathematics
1 answer:
mel-nik [20]3 years ago
7 0

Answer: (1/3,2)

Step-by-step explanation:

Let O(x,y) be the circumference of the triangle PQR,

Thus, by the property of circumcenter all the vertices of the triangle are at same distance from this circumcenter.

Thus, PO = QO

By the distance formula,

(x+2)^2+(y-5)^2 = (x-4)^2+(y-1)^2

\impliesx^2+ 4x + 4 + y^2+ 25 - 10 y = x^2+16 - 8 x + y^2+1 - 2y

\implies 4x + 4 + 25 - 10 y = 16 - 8 x + 1 - 2y

\implies 4x +8x-10y+2y = 16 + 1 -25-4

\implies 12x - 8y = 17 - 29

\implies 12 x - 8 y = - 12---------(1)

Similarly, QO = RO

\implies (x-4)^2 + (y-1)^2 = (x+2)^2+(y+3)^2

\implies x^2 + 16 - 8x + y^2+ 1 - 2y = x^2+ 4 + 4 x +y^2+ 9 + 6 y

\implies 16 - 8x + 1 - 2y = 4 + 4 x + 9 + 6 y

\implies - 8x -4x-2y-6y=4+9-16-1

\implies -12 x - 8 y = 13 - 17

\implies 12 x + 8 y = 4   ------------(2)

By adding equation (1) and (2),

24 x = - 8

x = 1/3

By putting this value in equation (1),

We get,

Thus, 4 - 8 y = -12

8 y = 16

y = 2

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