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melamori03 [73]
3 years ago
4

The probability that a randomly selected person has high blood pressure (the event H) is P(H) = 0.3 and the probability that a r

andomly selected person is a runner (the event R) is P(R) = 0.5. The probability that a randomly selected person has high blood pressure and is a runner is 0.2. Find the probability that a randomly selected person is a runner, given that he has high blood pressure.
Mathematics
1 answer:
musickatia [10]3 years ago
4 0

Answer: 2/3 = 0,67

Step-by-step explanation: We have P(H) = 0,3 and P(R) = 0,5.

P(High blood pressure and runner) = P(H∩R) = 0,2

The problem asks for P(runner, given he has high blood pressure) = P(R|H). This conditional probability is given by the formula:

P(A|B) = <u>P(A∩B)</u>

               P(B)      

In this case, P(R|H) = <u>P(H∩R)</u> = <u>0,2 </u>= <u>2</u> = 0,67

                                   P(H)        0,3    3  

             

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