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4 years ago

Please help! Will give Brainliest!!

Mathematics

1 answer:

Valentin [98]4 years ago

6 0

Answer:

$133507.33

Step-by-step explanation:

x = number of 6 month periods

y = total money in account

After 10 years:

$y = 300x(1.09)^x$

$y = 300(20)(1.09)^2^0$

$y = 6000(5.60441077)$

$y = 33626.46$

After 18 years:

$y = 33626.46(1.09)^x$

$y = 33626.46(1.09)^1^6$

$y = 33626.46(3.97030588)$

$y = 133507.33$

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Case 2: Diagonal $\overline{DB}$ is formed by connecting the vertices formed by the meeting points of the sides with equal lengths.
Call the intersection point of $\overline{DB}$ and $\overline{AC}$ E. We will focus on two triangles, namely $\triangle ADE$ and $\triangle ABE$ . Since diagonals intersect perpendicularly, these triangles are right triangles. One of them has a hypotenuse of $29$ , and the other has a hypotenuse of $25$ . They both share a leg that is half of $\overline{AC}$ because $\overline{DB}$ bisects $\overline{AC}$ . Let $AE=y$ and the non-shared leg of the right triangle with a hypotenuse of $29$ equal $x$ . Since $DB=40$ , the non-shared leg of the other right triangle (the one with a hypotenuse of $25$ ) has a length of $40-x$ . Using the Pythagorean Theorem, we can get the equations $x^2+y^2=29^2$ and $(40-x)^2+y^2=25^2$ . These can simplify to $x^2+y^2=841$ and $1600-80x+x^2 + y^2=625$ . Isolating the term $y^2$ , we can get $y^2=841-x^2$ and $y^2=625-x^2+80x-1600$ . The latter can simplify to $y^2=-975-x^2+80x$ . Using substitution, we can combine the two equations into one and get $841-x^2=-975-x^2+80x$ . We can simplify that to $80x=1816$ , meaning $x=22.7$ . However, we are looking for $2y$ ( $y$ is only half of $\overline{AC}$ ). We can solve for $y$ using the Pythagorean Theorem and the triangle with a hypotenuse of $29$ and a leg of $22.7$ . We get $y \approx 18.05$ , meaning $\overline{AC}=2y \approx 36.1 \text{ inches}$ , our final answer.

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Step-by-step explanation:

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