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3 years ago

Please help! Will give Brainliest!!

Mathematics

1 answer:

Valentin [98]3 years ago

6 0

Answer:

$133507.33

Step-by-step explanation:

x = number of 6 month periods

y = total money in account

After 10 years:

$y = 300x(1.09)^x$

$y = 300(20)(1.09)^2^0$

$y = 6000(5.60441077)$

$y = 33626.46$

After 18 years:

$y = 33626.46(1.09)^x$

$y = 33626.46(1.09)^1^6$

$y = 33626.46(3.97030588)$

$y = 133507.33$

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How many gallons of a 70% antifreeze solution must be mixed with 60 gallons of 20% antifreeze to get a mixture that is 60% a

Flura [38]

We have 60 gallons of 20% antifreeze.

How much 70% antifreeze do we add to get 60% antifreeze?

We'll make "x" the gallons of 70% we must add.

.20 * 60 + .70 x = .60 * (60 + x)

12 + .70x = 36 + .60x

.10x = 24

x = 240 gallons of 70% antifreeze.

Source

1728.com/mixture.htm (see example B)

4 0

3 years ago

3 letters without replacement 4 letters A B C D how many ways can this be done if the order of the choices matters

Veseljchak [2.6K]

Answer:

Since the order of choice matters, we will permute the values. a bit more explanation for this:

If the order of choice did NOT matter, ABC and BCA will be counted as one since order of choice does NOT matter

Since order of choice does matter, ABC , BCA and CAB are all different possibilities for the arrangement of the same 3 letters

Since we have 3 slots:

___ ___ ___

Now, for the first slot. You can out either one if the 4 alphabets in the first slot since no slot has been used as of now

So:

_4_ ___ ___

**Keep in mind that the 4 is the possible number of values this slot can have**

Now that one slot has been used, one of the 4 alphabets has been used and since we are not allowed to repeat the same alphabets, we are left with 3 more alphabets

we can put any one of the 3 alphabets in this second slot, Hence:

_4_ _3_ ___

Now that 2 of the 4 alphabets have been used, we are left with only 2 alphabets, so there are only 2 possible alphabets for slot 3

Therefore:

_4_ _3_ _2_

Now that we know the possible alphabets for all 3 slots, we will multiply them with each other to get the total possible number of 3 - alphabet words we can make with 4 alphabets

Total possible words = 4 * 3 * 2

Total possible words = 24

We could've used the formula for Permutation as well

8 0

3 years ago

A company manufacturers video games with a current defect rate of 0.95%. To make sure as few defective video games are delivered

RSB [31]

There would be about 19 defective products delivered.

First, let's start with the number of defective games.
100000 x 0.0095 = 950

Now, the test will catch 98% of those defects. That means 2% of the defects will get through to the consumers.
0.02 x 950 = 19

3 0

3 years ago

Read 2 more answers

out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i

Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.