All categories

3 years ago

Analyze this student's work. What did the student do correctly? What did he do incorrectly?

Mathematics

1 answer:

saw5 [17]3 years ago

8 0

I don’t think he did distributive property

You might be interested in

tapes-r-us is have a sale on hq tape players. The regular price is $60. The discount is $18. What percent discount is this?

olga nikolaevna [1]

The discount is 30%

Step-by-step explanation:

Given

Price of tape = $60

Discount = $18

In order to find the percentage, we will use the percentage formula

$Percentage = \frac{discount}{Price}*100\\= \frac{18}{60} *100\\=0.3 * 100\\= 30\%$

Hence,

The discount is 30%

Keywords: Percent, sale

Learn more about percentage at:

#LearnwithBrainly

7 0

3 years ago

Solve the formula for R. P=R-C

Dimas [21]

Answer:

R=P+C

Step-by-step explanation:

These ones are really simple. To solve these you just need to get a certain value by itself and in this case, it is R. To solve this just add C because it is negative and make sure to add it to both sides and there's your answer.

8 0

3 years ago

Four times the quantity x plus two is equal to ten

Degger [83]

Answer: 4x+2=10

Step-by-step explanation:

5 0

3 years ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0

3 years ago

What is the first ordered pair and the second ordered pair?

Delvig [45]

When x=-5, y=(1/5)*(-5)-1=-2, so the first order pair is (-5,-2)
when y=-1, -1=(1/5)x-1, (1/5)x=0, x=0, so the second ordered pair is (0, -1)

7 0

3 years ago