Just look at the picture it doesn’t have words

Is a square a type of rectangle or is a rectangle a type of square? Explain why or why not?

GaryK [48]

Answer:

A square is a rectangle.

Step-by-step explanation:

A square is a quadrilateral with all four angles right angles and all four sides of the same length. So a square is a special kind of rectangle, it is one where all the sides have the same length. Which means, every square is a rectangle because it is a quadrilateral with all four angles right angles.

4 0

3 years ago

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45 + 60 = 15 x ___ + 15 x ___

tia_tia [17]

Answer:45+60=15x+15x

Step 1: Simplify both sides of the equation.

45+60=15x+15x

(45+60)=(15x+15x)(Combine Like Terms)

105=30x

Step 2: Flip the equation.

30x=105

Step 3: Divide both sides by 30.

30x/30= 105/30

x= 7/2

Answer:

x= 7/2

may i have brainliest please

3 0

3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

docker41 [41]

Answer:

The answer is A.

Step-by-step explanation:

The first graph was dilated by 1/2, therefore the answer is A

5 0

3 years ago

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Graph the function. Describe its position relative to the graph of the indicated basic function.

masya89 [10]

Answer:

The answer is (b) moved right 3 units and moved down 3 units

Step-by-step explanation:

∵ f(x) = 4^x ⇒ red in the graph

∵ f(x) = 4^(x-3) - 3 ⇒ blue in the graph

∵ x becomes x - 3 ⇒ means:

The graph moved right 3 units

∵ f(x) = 4^x becomes 4^(x-3) - 3 ⇒ means:

The graph moved down 3 units

∴ The answer is (b)

9 0

3 years ago

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Anettt [7]

Answer:

Choice C: approximately 121 green beans will be 13 centimeters or shorter.

Step-by-step explanation:

What's the probability that a green bean from this sale is shorter than 13 centimeters?

Let the length of a green bean be $X$ centimeters.

$X$ follows a normal distribution with

mean $\mu = 11.2$ and
standard deviation $\sigma = 2.1$ .

In other words,

$X\sim \text{N}(11.2, 2.1^{2})$ ,

and the probability in question is $X \le 13$ .

Z-score table approach:

Find the z-score of this measurement:

$\displaystyle z= \frac{x-\mu}{\sigma} = \frac{13-11.2}{2.1} = 0.857143$ . Closest to 0.86.

Look up the z-score in a table. Keep in mind that entries on a typical z-score table gives the probability of the left tail, which is the chance that $Z$ will be less than or equal to the z-score in question. (In case the question is asking for the probability that $Z$ is greater than the z-score, subtract the value from table from 1.)

$P(X\le 13) = P(Z \le 0.857143) \approx 0.8051$ .

"Technology" Approach

Depending on the manufacturer, the steps generally include:

Locate the cumulative probability function (cdf) for normal distributions.
Enter the lower and upper bound. The lower bound shall be a very negative number such as $-10^{9}$ . For the upper bound, enter $13$
Enter the mean and standard deviation (or variance if required).
Evaluate.

For example, on a Texas Instruments TI-84, evaluating $\text{normalcdf})(-1\text{E}99,\;13,\;11.2,\;2.1 )$ gives $0.804317$ .

As a result,

$P(X\le 13) = 0.804317$ .

Number of green beans that are shorter than 13 centimeters:

Assume that the length of green beans for sale are independent of each other. The probability that each green bean is shorter than 13 centimeters is constant. As a result, the number of green beans out of 150 that are shorter than 13 centimeters follow a binomial distribution.

Number of trials $n$ : 150.
Probability of success $p$ : 0.804317.

Let $Y$ be the number of green beans out of this 150 that are shorter than 13 centimeters. $Y\sim\text{B}(150,0.804317)$ .

The expected value of a binomial random variable is the product of the number of trials and the probability of success on each trial. In other words,

$E(Y) = n\cdot p = 150 \times 0.804317 = 120.648\approx 121$

The expected number of green beans out of this 150 that are shorter than 13 centimeters will thus be approximately 121.

7 0

3 years ago