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3 years ago

This table represents a quadratic function.

Mathematics

1 answer:

AVprozaik [17]3 years ago

7 0

Answer:

B. 1/2

Step-by-step explanation:

y = ax^2 + bx + c

14 = a(0)^2 + b(0) + c

c = 14

10.5 = a(1)^2 + b(1) + 14

10.5 = a + b + 14 ____(i)

8 = a(2)^2 + b(2) + 14

8 = 4a + 2b + 14

4 = 2a + b + 7 ___ (ii)

i - ii

10.5 - 4 = -a + 7

6.5 = -a + 7

a = 7- 6.5

a = 0.5

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Rewrite in polar form: x^2+y^2-2y=7

Alchen [17]

X²+y²-2y=7
using the formula that links Cartesian to Polar coordinates
x=rcosθ and y=r sin θ
substituting into our expression we get:
(r cos θ)²+(r sin θ)²-2rsinθ=7
expanding the brackets we obtain:
r²cos²θ+r²sin²θ=7+2rsinθ
r²(cos²θ+sin²θ)=7+2rsinθ
using trigonometric identity:
cos²θ+sin²θ=1
thus
r²=2rsinθ+7
Answer: r²=2rsinθ+7

8 0

3 years ago

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What is the value of x? 1/3x-2/3=-18 ( please help it’s due tomorrow)

Nikolay [14]

X=56 is the answer :)

4 0

3 years ago

The ratio of boys to girls in Anaya’s class is 10 to 15. There are 20 boys how many girls are there

ASHA 777 [7]

Answer:

30 girls

Step-by-step explanation:

10 x 2= 20

15x2=30

For every 10 boys there are 15 girls. since 20 is just 10 multiplied by 2 you can multiply 15 by 2

7 0

3 years ago

if the diameter of the front wheels on the locomotive is 4 ft what is the diameter of the front wheels on the model. Express the

Leto [7]

Question is Incomplete, Complete question is given below.

Consider a model of a train locomotive that has a similarity transformation map of x arrow right 48x from the model to the actual locomotive when answering the question.

If the diameter of the front wheels on the locomotive is 4 feet, what is the diameter of the front wheels on the model? Express the answer in inches.

Answer:

The diameter of front wheel on the model is 1 inch.

Step-by-step explanation:

Given:

Let diameter of the front wheel on the model be 'x'.

Actual diameter of front wheel = 4 feet

Now given that ratio model to actual = $\frac{x}{48x}= \frac{1}{48}$

Now we can say that ratio model to actual is equal to ratio of model diameter of front wheel to actual diameter of front wheel.

framing in equation form we get;

$\frac{x}{4}=\frac{1}{48}\\\\x=\frac{4}{48} = \frac{1}{12} \ ft.$

Now we know that;

$\frac{1}{12}\ ft = 1 \ in.$

Hence The diameter of front wheel on the model is 1 inch.

6 0

3 years ago

X^2+4=square root 13

beks73 [17]

Answer:

$\large\boxed{x=-\sqrt{\sqrt{13}-4}}\ \vee\ x=\sqrt{\sqrt{13}-4}}$

Step-by-step explanation:

$x^2+4=\sqrt{13}\qquad\text{subtract 4 from both sides}\\\\x^2+4-4=\sqrt{13}-4\\\\x^2=\sqrt{13}-4\Rightarrow x=-\sqrt{\sqrt{13}-4}}\ \vee\ x=\sqrt{\sqrt{13}-4}$

5 0

3 years ago