So here first you have to have same denominators to subtract and add.
to make same denominator you have to multiply something to them which meets up to their lowest common multiple (LCM). so here the easiest thing is multiply each denominator to the other but remember you have to multiply them to the numerator too.
3×9/5×9-2×5/9×5
so it becomes
27/45-10/45
17/45
as you cant bring to its simplest form since the answer in a prime no. leave it like that.
Consider the following functions. f=[(-1,1),(1,-2),(3,-4) and g=[(5,0),(-3,4),(1,1),(-4,1)} Find (f-g)(1) =
Vilka [71]
The difference between the functions give:
(f - g)(1) = f(1) - g(1) = -3
<h3>
How to find the difference between the functions?</h3>
For two functions f(x) and g(x), the difference is defined as:
(f - g)(x) = f(x) - g(x).
Then:
(f - g)(1) = f(1) - g(1)
By looking at the given tables, we know that:
f(1) = -2
g(1) = 1
Replacing that we get:
(f - g)(1) = f(1) - g(1) = -2 - 1 = -3
If you want to learn more about difference of functions:
brainly.com/question/17431959
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Step-by-step explanation:
Susan needs to walk a total distance of 1/2 of a mile. She has walked 1/8 of a mile so far. How much further does she have to go? Simplify the fraction if possible.
Answer:1 is called the first term of the proportion, 2 is the second term, 5 is the third, and 10, the fourth. We say that 5 corresponds to 1, and 10 corresponds to 2.
Step-by-step explanation:
1 is called the first term of the proportion, 2 is the second term, 5 is the third, and 10, the fourth. We say that 5 corresponds to 1, and 10 corresponds to 2.
Answer:
a) x = 1.52
b) s = 1.16
Step-by-step explanation:
We have that:
5 students watched 0 movies.
9 students watched 1 movie.
5 students watched 2 movies.
5 students watched 3 movies.
1 student watched 4 movies.
(a) Find the sample mean x.
Sum divided by the number of students. So
(b) Find the approximate sample standard deviation, s.
Standard deviation of the sample.
Square root of the sum of the squares of the values subtracted from the mean, divided by the sample size subtracted by 1. So
