PLEASE HELP!!!! Write a rule for adding an even and an odd integer.

Jessica was sitting in row 9, seat 3 at a soccer game when she discovered her ticket was for row 1, seat 1. Write a rule to desc

Westkost [7]

rule is to shift 8 units left & , shift 2 units down , Correct option C) T<-8,-2> (Jessica) ,

Step-by-step explanation:

Here we have , Jessica was sitting in row 9, seat 3 at a soccer game when she discovered her ticket was for row 1, seat 1. We need to Write a rule to describe the translation needed to put her in the proper seat. Let's do this:

Suppose the above problem in coordinate system where we have a point $P(9,3)$ , And we need to write rule for translation of this point to $Q(1,1)$ .

Let , $(x,y)=(9,3)$ , Now shift 8 units left i.e.

⇒ $(x,y)=(9,3)$

⇒ $(x-8,y)=(9-8,3)$

⇒ $(x-8,y)=(1,3)$

Now , shift 2 units down i.e.

⇒ $(x-8,y)=(1,3)$

⇒ $(x-8,y-2)=(1,3-2)$

⇒ $(x-8,y-2)=(1,1)$

Therefore , rule is to shift 8 units left & , shift 2 units down , Correct option C) T<-8,-2> (Jessica) ,

4 0

3 years ago

0 A public beach in Arkansas charges non- residents $12 per day for a fishing license and $3.50 per day for live bait. Arkansas

vfiekz [6]

Non Residents:
f(x)= money in $ paid.
x=number of days.

f(x)=x(12+3.5)=15.5 x

f(x)=15.5x

Arkansas residents
f(x)=money in $ paid.
x=number of days.

f(X)=x+174

Now, we equate functions:

15.5x=x+174 (this is the equation)
15.5x-x=174
14.5x=174
x=174 / 14.5=12

Answer: the number of days is 12 days. The ecuation has one solution, because when I has solved it, I have had one solution.

6 0

4 years ago

PLEASE help with these questions?? there are 7 of them! Thank you!!

svetlana [45]

We know in these kind of triangles that have a 90 degrees angle, we can do:

${a}^{2} + {b}^{2} = {c}^{2}$

so the first question:

$\sqrt{ {99}^{2} + {20}^{2} } = 101$

and then:

$b = \sqrt{ {17}^{2} - {15}^{2} } = 8$

so , when you want to rationalize , usually you must multiply the irrational factor as 1:

$\frac{ \sqrt{15} }{ \sqrt{15} } = 1$

so , now multiply:

$\frac{3}{ \sqrt{15} } \times \frac{ \sqrt{15} }{ \sqrt{15} } = \frac{3 \sqrt{15} }{15} = \frac{ \sqrt{15} }{5}$

in the next question,we know negative numbers in radical don't have any solution so 2 is correct,

4 0

3 years ago

Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 4x3 − 6x2 − 24x + 1, [−2, 3] absolute m

Agata [3.3K]

When looking for extremes on an interval, one must examine the turning points and the values of the function at the ends of the interval. Here the turning points are where the derivative is zero:. j

... 12x² -12x -24 = 0

... 12(x -2)(x +1) = 0

Since the turning points, x=-1, x=2, are in the interval we have four function values to compute.

... f(-2) = ((4(-2) -6)(-2) -24)(-2) +1 = -7

... f(-1) = ((4(-1) -6)(-1) -24)(-1) +1 = 15

... f(2) = ((4(2) -6)(2) -24)(2) +1 = -39

... f(3) = ((4(3) -6)(3) -24)(3) +1 = -17

This shows the extremes to be at the turning points.

The absolute minimum value is -39 at x=2.

The absolute maximum value is 15 at x=-1.

7 0

3 years ago

How do you do this question?

Alex Ar [27]

Step-by-step explanation:

(a) dP/dt = kP (1 − P/L)

L is the carrying capacity (20 billion = 20,000 million).

Since P₀ is small compared to L, we can approximate the initial rate as:

(dP/dt)₀ ≈ kP₀

Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.

20 = k (6,100)

k = 1/305

dP/dt = 1/305 P (1 − (P/20,000))

(b) P(t) = 20,000 / (1 + Ce^(-t/305))

6,100 = 20,000 / (1 + C)

C = 2.279

P(t) = 20,000 / (1 + 2.279e^(-t/305))

P(10) = 20,000 / (1 + 2.279e^(-10/305))

P(10) = 6240 million

P(10) = 6.24 billion

This is less than the actual population of 6.9 billion.

(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))

P(100) = 7570 million = 7.57 billion

P(600) = 20,000 / (1 + 2.279e^(-600/305))

P(600) = 15170 million = 15.17 billion

7 0

3 years ago