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3 years ago

3m-2x for m = 5 and x = 4

Mathematics

1 answer:

kipiarov [429]3 years ago

3 0

M = 5 and x = 4

3(5) - 2(4)
15 - 8 = 7

I hope this helps!

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C, -2

Step-by-step explanation:

-4x + 7 = 2y - 3

-4x + 10 = 2y

-2y = 4x - 10

y = -2x + 5

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svet-max [94.6K]

We need a combination of coins that equal 65 cents.

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3 years ago

Solve the system by using elementary row operations on the equations. Follow the systematic elimination procedure

Umnica [9.8K]

Answer:

The solution of the Given matrix

( x₁ , x ₂ ) = ( - 5 , 4 )

Step-by-step explanation:

Step(i):-

Given equations are x₁+4 x₂ = 11 ...(i)

2 x₁ + 7 x₂= 18 ...(ii)

The matrix form

A X = B

$\left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]$

Step(ii):-

$\left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]$

The Augmented Matrix form is

$[AB] = \left[\begin{array}{ccc}1&4&11\\2&7&18\\\end{array}\right]$

Apply Row operations, R₂ → R₂-2 R₁

$[AB] = \left[\begin{array}{ccc}1&4&11\\0&-1&-4\\\end{array}\right]$

The matrix form

$\left[\begin{array}{ccc}1&4\\0&-1\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\-4\\\end{array}\right]$

The equations are

x₁ + 4 x₂ = 11 ...(a)

- x ₂ = - 4

x ₂ = 4

Substitute x ₂ = 4 in equation (a)

x₁ + 4 x₂ = 11

x₁ = 11 - 16

x₁ = -5

Final answer:-

The solution of the Given matrix

( x₁ , x ₂ ) = ( - 5 , 4 )

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3 years ago

An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden

adoni [48]

Answer: The accident proportion differ between the two age groups is 0.11.

Step-by-step explanation:

Since we have given that

Number of clients under 18 years of age = 500

Number of clients had had an accident = 180

Proportion of client had an accident = $\dfrac{180}{500}=\dfrac{18}{50}$

Number of clients aged 18 and older = 600

Number of clients had had an accident = 150

Proportion of client had an accident = $\dfrac{150}{600}=\dfrac{15}{60}$

So, According to question, we get that

Difference between the two age groups proportions would be :

$\dfrac{18}{50}-\dfrac{15}{60}\\\\=\dfrac{108-75}{300}\\\\=\dfrac{33}{300}\\\\=\dfrac{11}{100}$

Hence, the accident proportion differ between the two age groups is 0.11.

8 0

2 years ago