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Tomtit [17]
3 years ago
6

A sociologist polled a random sample of people and asked them their age and annual income. The two-way frequency table below sho

ws the results. Annual income vs. age group Less than $50,000 At least $50,000 Total Ages 44 and under 148 68 216 Ages 45 and above 38 94 132 Total 186 162 348 Which of the following statements is true of those polled? Choose 1 answer: А A person with an annual income of less than $50,000 is more likely to be 45 years old or above. B A person in the 44 and under age group is more likely to to have an annual income of at least $50,000​
Mathematics
2 answers:
myrzilka [38]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Iteru [2.4K]3 years ago
6 0

Answer:

C A person with an annual income of at least \$50{,}000$50,000dollar sign, 50, comma, 000 is more likely to be 454545 years old or above

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Identify the graph of the equation. What is the angle of rotation for the equation?
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

A

3 0
4 years ago
A triangle has an angle that measures 90°. The other two angles are in a ratio of 2:7. What are the measures of those two angles
marin [14]

Answer:

70° and 20°

let the other 2 angles be 7x and 2x

90+7x+2x=180

9x=180-90

x=90/9

x=10

7x=7x10

70

2x=2×10

2p

3 0
2 years ago
Please Help !! <br>The picture of the question is attached. ​
kirza4 [7]

Answer:

x = 90°

Step-by-step explanation:

Using the identity

cos²x = 1 - sin²x

Given

cos²x - sin x + 1 = 0

1 - sin²x - sin x + 1 = 0

- sin²x - sin x + 2 = 0 ← quadratic equation in sin x ( multiply through by - 1 )

sin²x + sin x - 2 = 0 ← in standard form

(sinx + 2)(sinx - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

sinx + 2 = 0 ⇒ sinx = - 2 ← has no solution as - 1 ≤ x ≤ 1

sinx - 1 = 0 ⇒ sinx = 1 ⇒ x = 90°

solution is x = 90°

3 0
3 years ago
Experts estimate that when levees break in the aftermath of a hurricane, water can flow into a city at a peak rate of 8 billion
worty [1.4K]

Full question:

Experts estimate that when levees break in the aftermath of a hurricane, water can flow into a city at a peak rate of 8 billion gallons per day. There are 7.5 gallons in 1 cubic foot. Use this information to complete parts (a) and (b) below. Click the loon to view the USCS measurements a. Find the flow rate in units of cubic feet per second (cs). Compare this flow rate to a river with an average flow rate of 30,000 cfs. The flow rate is cfs, which is approximately % of the flow rate of the river (Round to the nearest whole number as needed.) b. Assume that the flooded part of the city had an area of 8 square miles Estimate how much in foot) the water level rose in one day at the given flow rate. The water level rose approximately (Round to the nearest tenth as needed.)

Answer and explanation:

Peak rate= 8 billion gallons per day

7.5 gallons = 1 cubic feet

Given that

8 billion gallons= 24 hrs

And 24 hrs = 86400 seconds

8 billion gallons =86400 seconds

In one second =8000,000,000/86400

= 92,592.593 gallons

Units of cubic feet per second =92592.593/7.5= 12345.68 cubic feets

Therefore the flow rate in cubic feet per second = 12345.68 cubic feets

If we compare this to 30000 cubic feet per second flow rate of the river, it would be 12345.68/30000*100/1= 41.152% of the flow rate of the river

B) Given that the total cubic feet per day =86400*12345.68= 1066666752 cubic feet

And 1 mile = 5280 feet

1 square mile = 27878400 square feet

8 square miles = 8 × 27878400 = 223027200 square feet

To calculate the height,

The number of foot by which the water level rose in one day is

1066666752/223027200 = 4.7826 feet per day

5 0
3 years ago
Select the functions that have a value of 0.
Sphinxa [80]

Answer:

<h2>cos90° = 0°, tan0° = 0°,</h2><h2>cos(-90°) = 0°, cot270° = 0°</h2>

Step-by-step explanation:

k\in\mathbb{Z}\\\\\sin x=0\iff x=180^ok\\\\\cos x=0\iff x=90^o+180^ok\\\\\tan x=0\iff x=180^ok\\\\\cot x=0\iff x=90^o+180^ok\\\\\csc x\neq0\ \text{for}\ x\in\mathbb{R}-\{180^ok\}\\========================\\\\\sin270^o\neq0\\\\\cos90^o=\cos(90^o+180^o\cdot0)=0\\\\\tan0^o=\tan(180^o\cdot0)=0\\\\\csc(-180^o)\neq0\\\\\cos(-90^o)=\cos(90^o-180^o)=\cos(90^o+180^o\cdot(-1))=0\\\\\cot270^o=\cot(90^o+180^o)=0

3 0
3 years ago
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