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melamori03 [73]
3 years ago
9

A jar contains only quarters and dimes. The jar contains a total of 92 coins. The value of all the coins is 14$. How many quarte

rs and dimes are in the jar?
Mathematics
1 answer:
skad [1K]3 years ago
6 0

Answer:

read the explanation ya bean bag

Step-by-step explanation:

we can set up some equations

lets say that q=one quarter and d=one dime

there are 92 coins so q+d=92

for each quarter, there are 25 cents added towards the 14 dollars

for each dime, there are 10 cents added towards the 14 dollars

14 dollars is equal to 1400 cents

using all this information, we can write the following equation:

25q+10d=1400

we can simplify this to 5q+2d=280

remember that q+d=92, so let's take out the extra dimes: 3q+2(q+d)=280 or 3q+2*92=280 or 3q+184=280 or 3q=96 or q=32

there are 32 quarters, so we can subtract 32 from 92 to figure out how many dimes we have

92-32=60 dimes

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Find the value of x in the equation x⁄ 4 + x⁄14 + x⁄17 = 71
Morgarella [4.7K]

Hello from MrBillDoesMath!

Answer:

33769/181

Discussion:

Each term contains "x" so factoring it out gives

x( 1/4 + 1/14 + 1/17)  = 71       (*)

Use common factor (17*14*4  = 952) as the denominator to combine terms:

1/4 =  (17*14)/ 952  = 238/952

1/14 = (17*4)/952 = 68/952

1/17 = (14*4)/952  = 56/952

so 1/4 + 1/14 + 1/17 =    (238 + 68 + 56)/ 952 =  362/952 = 181/476

Substituting in (*) gives

x ( 181/476)  = 71                       => multiply both sides by 476/181

x = (71 * 476)/181                       => 71* 476 =33769

x = 33769/181

Thank you,

MrB

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