Using derivatives, it is found that:
i) 
ii) 9 m/s.
iii) 
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:
item i:
Velocity is the <u>derivative of the position</u>, hence:
Item ii:
The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:
Item iv:
The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:
Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
Answer:
exponential function
Step-by-step explanation:
geometric sequence
An = A1 * r^(n-1)
common ratio is 2
A1 = 1st term
nagwa
mthway
Well. If you get 29% of 5 cars that is 145%. This was a little confusing but I am defiantly sure it is correct. I like to use simpler numbers to see if I am doing the work right. So I said if he has a 50 % likely hood to find a car that was expired and had 1 car. It would be 50 percent. Now if he had 2nt got it the first time it would be a 100 % chance to find the car expired . Hope I didn’t co fuse you more
Answer:
Step-by-step explanation:
We have the statement AB turns clockwise to coincide with BC.
= ABD + DBC
= 33.3° + 30.6°
= 63.9°
Now we have the statement a point E is drawn directly opposite point C. B, E, and C are on the same straight line
EBC is a straight line, so sum of angles =180°
ABE + ABD + DBC = 180°
ABE + 33.3° + 30.6° = 180°
ABE + 63.9° = 180°
ABE = 180 - 63.1
ABE = 116.9° ....
