Answer:
1/12
Step-by-step explanation:
The probability of landing on tail = 1/2
The probability of rolling a 3 = 1/6
The probability of doing BOTH is 1/2 x 1/6 = 1/12
Answer:
The answer is n = 17
Step-by-step explanation:
Divide both sides by the numeric factor on the left side, then solve.
Hoped this helped!
brainly, please?
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
Given:
Consider the below figure attached with this question.
To find:
The value of 
.
Solution:
The given functions are:
Now,
We know that,
Adding 3 on both sides, we get
So, for all values of x.
Hence, the correct option is A.
The answer is EFD because the turn is counterclockwise, around point P
- Your welcome
