Slope intercept form is y=mx+b
you can later plug in values to make your own slope intercept form.
9514 1404 393
Answer:
y -8 = 1/5(x -3)
Step-by-step explanation:
The point-slope form of the equation of a line is ...
y -k = m(x -h) . . . . . . line through point (h, k) with slope m
The given equation y = 1/5(x +4) matches this form with m=1/5. The parallel line will have the same slope.
This means you want a line through point (3, 8) with slope 1/5. Putting these values in the point-slope form gives ...
y -8 = 1/5(x -3)
Answer:
no solutions
Step-by-step explanation:
Hi there!
We're given this system of equations:
x+y=3
4y=-4x-4
and we need to solve it (find the point where the lines intersect, as these are linear equations)
let's solve this system by substitution, where we will set one variable equal to an expression containing the other variable, substitute that expression to solve for the variable the expression contains, and then use the value of the solved variable to find the value of the first variable
we'll use the second equation (4y=-4x-4), as there is already only one variable on one side of the equation. Every number is multiplied by 4, so we'll divide both sides by 4
y=-x-1
now we have y set as an expression containing x
substitute -x-1 as y in x+y=3 to solve for x
x+-x-1=3
combine like terms
-1=3
This statement is untrue, meaning that the lines x+y=3 and 4y=-4x-4 won't intersect.
Therefore the answer is no solutions
Hope this helps! :)
The graph below shows the two equations graphed; they are parallel, which means they will never intersect. If they don't intersect, there's no common solution
The numbers are: "11" and "21" .
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Explanation:
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x + y = 32 ; Note: y is greater than "x";
y = 2x <span>− 1 ;
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We have: " x + y = 32" ;
Plug in "(2x </span><span>− 1)" for "y" ;
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</span>→ x + (2x <span>− 1) = 32 ;
</span>→ x + 1(2x − 1) = 32 ;
<span>
</span>→ x + 2x − 1 = 32 ;
<span>
</span>→ 1x + 2x − 1 = 32 ;
<span>
</span>→ 3x − 1 = 32 ;
<span>
Add "1" to each side of the equation ;
</span>→ 3x − 1 + 1 = 32 + 1 ;
<span>
</span>→ 3x = 33 ;
<span>
Divide each side of the equation by "3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
3x / 3 = 33 / 3 ;
x = 11 ;
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Now, let us solve for "y" ;
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Method 1)
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</span>We have: "x + y = 32" ;
<span>
We have "x = 11 " ;
Plug in "11" for "x" into the equation; to solve for "y" ;
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"x + y = 11 + y = 32 " ;
</span>→ y + 11 = 32 ;
<span>
Subtract "11" from each side of the equation;
</span>→ y + 11 − 11 = 32 <span>− 11 ;
</span><span>
</span>→ y = 21 ;
<span>____________________________________
So; the numbers are: "11" and "21" .
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Method 2) (and we can do this anyways to confirm our answer):
___________________________________________________
When we have: "</span>x = 11 " ; Let us solve for "y" ;
<span>___________________________________________________
We have the equation: "</span>y = 2x − 1 " ;
<span>
Plug in the value, "11", for "x", in this equation; to solve for "y" ;
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</span>→ y = 2(11) − 1 ;
<span>
</span>→ y = 22 − 1 ;
<span>
</span>→ y = 21
<span>____________________________________________
So, our answers are: "11" and "<span>21" .
</span>____________________________________________
Note: x + y = ? 32 ? ; </span>→ "11 + 21 = ? 32 ? " ; Yes!
<span>____________________________________________
Note: "y" is the larger number; y </span>> x ? ; → "21 <span>> 11 " ? Yes!
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