Answer:
length and width = 40 and 10 ft.
Step-by-step explanation:
The perimeter of a rectangular toddler play area is 100 feet.
Perimeter = 2(length + width)
Let the width = w
The length is 10 feet more than 3 times the width. Length = 10+(3w)
now put the values
100 = 2(10+3w + w)
100 = 2w + 20 + 6w
100 = (2w + 6w) + 20
100 = 8w + 20
8w = 100 - 20
w =
w = 10 feet.
Now Length = 10+ (3w)
= 10+( 3 × 10)
= 10 + 30
= 40 feet
Therefore, length = 40 feet and width = 10 feet
Answer:
hi. this is the way
Step-by-step explanation:
this is the process of doing it. hope you like it
Each term differs by -68 and the first term is -68, we have:

As an expession it's just -68n.
Answer:
Find what <u>both fractions</u> are <u>divisible</u> by.
Step-by-step explanation:
Take
and if needed, use a multiplication tabel to help you figure out what both numbers are divisible by. 5 and 15 are both divisible by 5. Now you can reduce the answer to
.
Hope this helps!
-Coconut;)
The valid conclusions for the manager based on the considered test is given by: Option
<h3>When do we perform one sample z-test?</h3>
One sample z-test is performed if the sample size is large enough (n > 30) and we want to know if the sample comes from the specific population.
For this case, we're specified that:
- Population mean =
= $150 - Population standard deviation =
= $30.20 - Sample mean =
= $160 - Sample size = n = 40 > 30
- Level of significance =
= 2.5% = 0.025 - We want to determine if the average customer spends more in his store than the national average.
Forming hypotheses:
- Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get:

- Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically

where
is the hypothesized population mean of the money his customer spends in his store.
The z-test statistic we get is:

The test is single tailed, (right tailed).
The critical value of z at level of significance 0.025 is 1.96
Since we've got 2.904 > 1.96, so we reject the null hypothesis.
(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).
Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.
Learn more about one-sample z-test here:
brainly.com/question/21477856