Answer:
x=-3/7 and y=_23/7
Step-by-step explanation:
y=-4x-5 and y=3x-2
using comparison method
-4x-5=3x-2
-4x-3x=-2+5
-7x=3
x=3/-7
substituting the value of x
y=3x-2
=3×(-3/7)-2
=-9/7-2
=-9-14/7
=-23/7
Answer:
wheres the problem
Step-by-step explanation:
The equation of a circle exists:
, where (h, k) be the center.
The center of the circle exists at (16, 30).
<h3>What is the equation of a circle?</h3>
Let, the equation of a circle exists:
, where (h, k) be the center.
We rewrite the equation and set them equal :
We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.
-2hx = -32x
h = -32/-2
⇒ h = 16.
-2ky = -60y
k = -60/-2
⇒ k = 30.
The center of the circle exists at (16, 30).
To learn more about center of the circle refer to:
brainly.com/question/10633821
#SPJ4
The first step to solving this is to multiply both sides of the equation by 3
8 + 10y = 9y - 12
now move the variable to the left side and change its sign
8 + 10y - 9y = -12
move the constant to the right side and change its sign
10y - 9y = -12 - 8
collect the like terms for y
y = -12 - 8 (it equals 1 when you subtract 10 from 9 which is the same is simply saying "y")
calculate the difference on the other side of the equals sign
y = -20
this means that the correct answer to your question is -20.
let me know if you have any further questions
:)
