The answer is (1/3). So first you need to determine the fraction of time the second person worked. Multiply (1/2)x(1/3) and you will get (1/6). All the values need to add up to 1, so you can make the equation (1/2)+(1/6)+x=1. Solve for x and you will get (1/3).
The lawyer makes approximately $11,656.67 a month. Hope this helps!
I think the correct answer from the choices listed above is option A. The statement that determines how many batches of cookies he can make would be that he <span> can make fewer than 13 batches of cookies. Hope this answers the question. Have a nice day.</span>
Answer:
to find the area of a polygon
formula: area = 1/2 x perimeter x apothem
Step-by-step explanation:
Here is what it means: Perimeter = the sum of the lengths of all the sides. Apothem = a segment that joins the polygon's center to the midpoint of any side that is perpendicular to that side.
Answer:
Using either method, we obtain: 
Step-by-step explanation:
a) By evaluating the integral:
![\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%5Cint%5Climits%5Et_0%20%7B%5Csqrt%5B8%5D%7Bu%5E3%7D%20%7D%20%5C%2C%20du)
The integral itself can be evaluated by writing the root and exponent of the variable u as: ![\sqrt[8]{u^3} =u^{\frac{3}{8}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bu%5E3%7D%20%3Du%5E%7B%5Cfrac%7B3%7D%7B8%7D)
Then, an antiderivative of this is: 
which evaluated between the limits of integration gives:

and now the derivative of this expression with respect to "t" is:

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:
"If f is continuous on [a,b] then

is continuous on [a,b], differentiable on (a,b) and 
Since this this function
is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:
