Answer:
hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to
Answer: v = 5v + 4u + 1.5sin(3t),
Step-by-step explanation:
u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1
v represents the "velocity function" i.e v = u'(t)
As v = u'(t)
<em>u' = v</em>
since <em>u' = v </em>
v' = u"
v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )
= 5v + 4u + 1.5sin(3t) ( noting that v = u' )
so v' = 5v + 4u + 1.5sin(3t)
d/dt
=
+
Given that u(1) = 1 and u'(1) = 2.5
since v = u'
v(1) = 2.5
note: the initial value for the vector valued function is given as
= ![\left[\begin{array}{ccc}1\\2.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C2.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Answer:
Option B is correct
Step-by-step explanation:
2x² - 6x + 3 = 0
Using Quadratic formula:
x = 
a = 2, b = -6, c = 3
x = 
x = 

x = 2.37

x = 0.63
3 because if you think about it, it's pretty much asking
what number multiplied by 9 will give you 27.
or 27 divided by 9.
She made her first mistake in step 2
-2x+5 =-11
add 5 to each side
-2x-5+5 = -11+5
-2x = -6 (not -16)
divide by -2
-2x/-2 = -6/-2
x = 3
She added 5 to 11 and got 16 and made it negative instead of subtracting 5 from 11 and making it negative