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Paha777 [63]
3 years ago
7

Suppose that the duration of a particular type of criminal trial is known to be normally distributed with a mean of 22 days and

a standard deviation of 6 days. 72% of all of these types of trials are completed within how many days
Mathematics
1 answer:
Alika [10]3 years ago
6 0

Answer:

25.5 days

Step-by-step explanation:

Mean number of days (μ) = 22 days

Standard deviation (σ) = 6 days

Z-score for the 72nd percentile (according to tabulated values) = 0.583

The z-score for any number of days, X, is determined by:

z=\frac{X-\mu}{\sigma}

The value of X that is greater than 72% of the trial times is:

0.583=\frac{X-22}{6}\\ X=25.5\ days

Therefore, 72% of all of these types of trials are completed within 25.5 days.

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Oduvanchick [21]

4y=8x
Isolate y by dividing both sides by 4
Y=2x

Sub every y with 2x

Answer is A

7 0
2 years ago
17, 18, 22, 31, 47 what is the next number
pogonyaev

Answer:

the next number is 47+ 16 =63

4 0
2 years ago
3x+y=4 <br> x+2y=-2<br> what is the answer
Taya2010 [7]

Answer:

2(3x+y=4)

1(x+2y=-2)

6x+2y=8

<u>(-) x+2y=-2</u>

<u>5x=10</u>

5

x=2

x+2y=-1

2+2y=-1

<u>-</u><u>2</u><u> -</u><u>2</u>

<u>2y=-</u><u>3</u>

2

y=-3/2

Step-by-step explanation:

  1. multiply the first equation by 2 to make y equal to each other.
  2. subtract to eliminate y
  3. divide by 5 to get x
  4. take one of the equations
  5. replace x by 2 to solve for y
3 0
3 years ago
PLS ANSWER FAST I WILL MARK THE BEST ONE BRAINLIEST PLS
Fudgin [204]

Answer:

E

Step-by-step explanation:

if we decidedly factor this expression-

4x^2+4xy+y^2

= (2x)^2 + 2*2xy + y^2

= (2x + y)^2

as you can see it is a perfect square so it can be grouped into (2x+y)^2

hence your solution is option e

8 0
3 years ago
Read 2 more answers
Someone please help. Please explain how I should do it!
Ede4ka [16]

Answer:

Step-by-step explanation:

if m and n are irrational number then the product of mn sometimes rational and sometime irrational

ex: √5 *√2=√10 irrational

ex: √8*√2=√16=4 rational

b-y=|x|+3

explain why |x|+3≥|x+3|

absolute value of any number is always positive

x           |x|+3          ≥            |x+3|

1              4              =               4             in this case equal

2             5                                5

-2             5             ≥                 1             in this case |x|+3≥|x+3|

in case of negative value of x then |x|+3>|x+3|

7 0
3 years ago
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