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sineoko [7]
4 years ago
14

The price of an item has been reduced by 30%. The original price was $70. What is the price of the item now?

Mathematics
2 answers:
Jlenok [28]4 years ago
8 0

Answer:

$41.25

Step-by-step explanation:

We can use this formula to solve this problem:

s

=

p

−

(

d

×

p

)

Where:

s

is the sales price: what we are solving for in this problem.

p

is the original price: $55 for this problem.

d

is the discount rate: 25% for this problem. "Percent" or "%" means "out of 100" or "per 100", Therefore 25% can be written as  

25

100

.

Substituting and calculating  

s

gives:

s

=

$

55

−

(

25

100

×

$

55

)

s

=

$

55

−

$

1375

100

s

=

$

55

−

$

13.75

s

=

$

41.25

qwelly [4]4 years ago
5 0

Answer:

\frac{30}{100}  \times 70 \\ 21 \\ 70 - 21 \\ 49

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Mr. Akika has 30 24-cent and 33-cent stamps all told. The stamps are worth $8.91. How many of each kind of stamp does he have?
riadik2000 [5.3K]

Answer:

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  • 33-cent: 19

Step-by-step explanation:

I find it easiest to solve these using the variable to represent the number of the most-expensive item. Let x represent the number of 33-cent stamps. Then the total value (in cents) is ...

  33x +24(30 -x) = 891

  9x = 171 . . . . . . . . . . . . . subtract 24(30), collect terms

  x = 19 . . . . . . . . . . . . divide by 9

  30-x = 11 . . . . . . . find the number of 24-cent stamps

Mr. Akika had 11 24-cent stamps and 19 33-cent stamps.

_____

<em>Additional comment</em>

You seem to have several of these to solve. They all have a similar solution.

If we let x represent the number of higher-value items, N, the total number of items, V the total value, and v1 and v2 the individual values (v2 > v1), the equation is ...

  v2(x) +v1(N -x) = V

  x(v2 -v1) = V -v1·N

  x = (V -v1·N)/(v2 -v1) . . . . generic solution

Using this formula in the problem here, we find ...

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7 0
2 years ago
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