$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

3 years ago

The members of the basketball team ordered 5 tuna sandwiches at $3.99 each, 5 fish tacos at $2.75 each, 3 salads at $2.70 each,

Oliga [24]

Firstly, $3.99 × 5 = $19.95

Second, $2.75 × 5 = $13.75

Third, $2.70 × 3 = $8.1 (Since it is just $8.1 that won't make sense so we'd add a 0 so It's $8.10.)

Then we do the last one which is 13 × $0.89 = $11.57.

So now since we are done multiplying we can add it all up.

The answer is $53.37 when we finish adding it up.

and I don't know what A number sentence is sorry :(

I took a long time typing this :< I hope this helps though! :D

7 0

2 years ago

Mr. Bobby plans to spend no more than $200 on pizza and soda for a party. Each pack of soda costs $5.00 and each pizza costs $8.

goldfiish [28.3K]

Answer:

6yr

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers