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natka813 [3]
3 years ago
10

Select the option for "?" that continues the pattern in each question.

Mathematics
1 answer:
Brut [27]3 years ago
4 0
1. 13
2. 9 or 38 not really sure
3.1595
4.. 810
You might be interested in
A farmer has a collapsable grain bag which can expand both vertically and horizontally as he needs it to. He wants to find a fun
bija089 [108]

Answer:

3x^{3}+15x^{2}+x+5

Step-by-step explanation:

We are told that the area of the bag can be represented by the function f(x)=3x^{2} +1 and as the bag is raised up its height can be represented by the function g(x)=x +5.

Since we know that we can find volume of cuboid by multiplying base area to its height. We are given area and height of bag as functions. Now we will find volume of the bag by multiplying these functions.  

\text{Volume of collapsible bag}=f(x)*g(x)  

\text{Volume of collapsible bag}=(3x^{2}+1)*(x +5)

After using distributive property we will get,

\text{Volume of collapsible bag}=3x^{2}(x+5)+1(x+5)

\text{Volume of collapsible bag}=3x^{3}+15x^{2}+x+5

Therefore, the collapsible bag can hold 3x^{3}+15x^{2}+x+5 grain.

6 0
3 years ago
I need help that is simple enough explnation
velikii [3]

Answer:

7 in both boxes

Step-by-step explanation:

In the picture, it shows

4 (x - 3) = 20

and then it shows

4 (x) - 4 (3) = 20

so practically you separate the x and 3 and put them in parentheses and then put a 4 next to both of them.

It should be the same as your question.

7 x (8 - 3)

and then separate 8 and 3 and put a 7 next to both of them.

( 7 x 8) - ( 7 x 3)

Hope it helps and have a great day! =D

~sunshine~

3 0
2 years ago
If y varies directly as x and y = 5.5 when x = 11, find x when y = 3.5
PtichkaEL [24]

Answer:

x=7

Step-by-step explanation:

y=mx

5.5=m×11

5.5÷11=m

m=1/2

y=mx

3.5=1/2×x

3.5÷1/2=x

x=7

4 0
2 years ago
Read 2 more answers
Can somebody please help me on this.?
rjkz [21]
Dont know im sorry i dont find the pattern

3 0
3 years ago
Twelve cans of peaches are placed into each box. Write a function rule for the number of boxes needed for c cans. How many boxes
Mars2501 [29]

C = # of cans

b = # of boxes                          

C  |  B    

12 |  1

24 | 2

36 | 3


12b = C

12b/12 = 1440/12

b = 120 boxes

for 1440 cans.

6 0
2 years ago
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