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grandymaker [24]
3 years ago
5

3+-1/1/3 the first half is 3+-1 the second half is 1/3

Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0
\bf \cfrac{3\pm1}{\frac{1}{3}}\implies 
\begin{cases}
\cfrac{3+1}{\frac{1}{3}}\\\\
\cfrac{3-1}{\frac{1}{3}}
\end{cases}\\\\
-------------------------------\\\\

\bf \cfrac{3+1}{\frac{1}{3}}\implies \cfrac{4}{\frac{1}{3}}\implies \cfrac{\frac{4}{1}}{\frac{1}{3}}\implies \cfrac{4}{1}\cdot \cfrac{3}{1}\implies \cfrac{4\cdot 3}{1\cdot 1}\implies \cfrac{12}{1}\implies \boxed{12}
\\\\\\
\cfrac{3-1}{\frac{1}{3}}\implies \cfrac{2}{\frac{1}{3}}\implies \cfrac{\frac{2}{1}}{\frac{1}{3}}\implies \cfrac{2}{1}\cdot \cfrac{3}{1}\implies \cfrac{2\cdot 3}{1\cdot 1}\implies \cfrac{6}{1}\implies \boxed{6}
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Diano4ka-milaya [45]

Answer:

An equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

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Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Given the line

6x+y=2

Simplifying the equation to write into the  slope-intercept form

y = -6x+2

So, the slope = -6

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus, the slope of the perpendicular line will be: -1/-6 = 1/6

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be

y-y_1=m\left(x-x_1\right)

substituting the values m = 1/6 and the point (6, -2)

y-\left(-2\right)=\frac{1}{6}\left(x-6\right)

y+2=\frac{1}{6}\left(x-6\right)

subtract 2 from both sides

y+2-2=\frac{1}{6}\left(x-6\right)-2

y=\frac{1}{6}x-3

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

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2 years ago
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andrezito [222]
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The remaining part of the substance is nickel:
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Using Ben's estimate, 0.2 g of nickel per gram of substance, we have
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