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marishachu [46]
2 years ago
7

Find the value of each variable for the right triangles. make sure all answers are in reduced radical form. show your work.

Mathematics
1 answer:
dimulka [17.4K]2 years ago
3 0
That's how you find the value for x
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An airplanes altitude changes -378 feet over 7 minutes. What was the mean change of altitude in feet per minute?
Natalija [7]
Average rate= change in alt / change in time

r=-378/7=-54ft/min
4 0
3 years ago
Read 2 more answers
Find the equivalent expression 9 ( 2a + 1
aivan3 [116]

Answer:

Equivalent expression of 9(2a+1) is, 18a+9

Step-by-step explanation:

The distributive property says that:

a \cdot (b+c) = a\cdot b + a\cdot c

Given the expression: 9(2a+1)

Apply the distributive property:

9 \cdot (2a) +9 \cdot 1

Simplify:

18a+9

Therefore, the equivalent expression of 9(2a+1) is, 18a+9

8 0
3 years ago
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What are the ratios for SIN A and COS A
miskamm [114]

Answer:

A

Step-by-step explanation:

A good trick for trigonometric functions is to remember SOHCAHTOA:

Sin=<u>O</u>pposite over <u>H</u>ypotenuse

Cos=<u>A</u>djacent over <u>H</u>ypotenuse

Tan=<u>O</u>pposite over <u>A</u>djacent

The red arrows on the attachment indicate where opposite, hypotenuse, and adjacent are for angle A.

So in this case, the sin of angle A (opposite over hypotenuse) would be \frac{24}{26} and cos A (adjacent over hypotenuse) would be \frac{10}{26}.

I hope this helps!

6 0
2 years ago
Tom has three times as many action figures as Jerry. If Tom has 27 action figures, how many does Jerry have?
weeeeeb [17]

Answer:

Step-by-step explanation:

3j = 27

j = 9

Jerry has 9 figures.

3 0
3 years ago
Write the explicit formula that represents the geometric sequence-2, 8, -32, 128
maks197457 [2]
Well,  since we know is a geometric sequence, we can always get the common ratio  of it by simply dividing one value by the one behind it... so let's do so, with say hmm -32 and 8  -32/8 = -4  <-- our common ratio

the first term is -2

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=-2\\&#10;r=-4&#10;\end{cases}\implies a_n=-2(-4)^{n-1}
4 0
3 years ago
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