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3 years ago

Help me pls I’m stuck

Mathematics

1 answer:

Sliva [168]3 years ago

8 0

Answer:

0.2666666666

Step-by-step explanation:

first 2÷9=0.2222222222

second-6/5=-1.2

third 0.2222222222×(-1.2)=0.2666666666

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An oil tank has to be drained for maintenance. The tank is shaped like a cylinder that is 4 ft long with a diameter of 2.2 ft. S

gavmur [86]

Answer:

$8\:\mathrm{minutes}$

Step-by-step explanation:

The volume of a cylinder is given as:

$r^2\cdot\pi\cdot h$

Since the diameter is $2.2$ , the radius is $\frac{2.2}{2}=1.1$ .

Therefore, the volume of this cylinder is:

$1.1^2\cdot 3.14\cdot 4=15.1976\:\mathrm{ft^3}$ , using $\pi=3.14$ as requested in the problem.

Since the tank is emptied at a constant rate of $1.5\:\mathrm{ft^3\:per\:minute}$ , it will take

$\frac{15.1976}{1.5}=7.5988=\fbox{$8\:\mathrm{minutes}$}$ to empty the tank.

8 0

3 years ago

Javier monthly net income is $1,500. He requests that his bank deposit 1/5 of his monthly earnings into his savings account. how

Harman [31]

1500 * 1/5
1500 * 0.2 = 300
300 * 12 = 3600
Javier contributes $3,600 a year to his savings.

5 0

3 years ago

A machine shop produces metal frames on two different machines. The average daily production on machine 1 is 300 frames, and the

statuscvo [17]

Answer:

The daily shop productivity is 480 frames

Step-by-step explanation:

The daily machine productivity refers to the TOTAL production made in a day.

The problem says that a shop produces metal on two different machines. It means that you must take into account the daily production of each one for finding the total production.

The first machine produces 300 frames in a day.

The second machine produces 180 frames in a day too.

So, if the first and the second machines are working together in a single day, the TOTAL daily production is the sum of the production of each one.

$production=300+180=480$

Thus, the daily shop productivity is 480 frames

4 0

3 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

What is the slope of the line on the graph

ella [17]

Answer:

The slope is 6

Step-by-step explanation:

The rise is 6 and the run is 1. 6/1

4 0

3 years ago

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