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Rom4ik [11]
3 years ago
15

Jay went on a diet and lost 5 pounds each month. Find Jay's net weight change in 6 months.

Mathematics
1 answer:
Goryan [66]3 years ago
7 0

Answer:

a 30 pound weight change in 1 month

Step-by-step explanation:

5 pounds

--------------- times 6 months  results in a 30 pound weight change in 1 month

 1 month

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01.05 what is the slope intercept form equation of the line that's passing through (1,3) and (3,7)
Butoxors [25]

Hello!

To find the slope-intercept form equation of the line that passes through the two points is found by first, calculating the slope using the slope formula and substitution, and secondly, finding the y-intercept of the equation through substitution.

Remember, slope-intercept form is written as: y = mx + b, where m is the slope and b is the y-intercept.

1. Find the slope

The slope formula is: \frac{y_{2}-y_{1}}{x_{2}-x_{1}}. To use this formula, you need two points and also, you need to assign these points to x_{1}, x_{2}, y_{1}, and y_{2}.

In this case, x_{1} and x_{1} is assigned to the ordered pair (1,3), while x_{2} and y_{2} is assigned to (3, 7). After assigning these points, you can substitute the pairs into the formula and simplify.

\frac{7-3}{3-1} =\frac{4}{2} = 2

The slope of these two points is 2.

2. Find the y-intercept

To find the y-intercept, you substitute an ordered pair into the slope-intercept equation with the slope that was just calculated. We can use either ordered pair because it will result in the same y-intercept.

y = 2x + b (substitute)

3 = 2(1) + b (simplify)

3 = 2 + b (subtract 2 from both sides)

1 = b

The y-intercept of the two points is (0, 1).

With the necessary values to complete the equation, we can write the final equation.

The slope-intercept form equation of the line that passes through the points (1, 3) and (3, 7) is y = 2x + 1.

7 0
3 years ago
Simplify 9 + 6k +3 +212 +3 +7​
melisa1 [442]

Answer:

6k+234

Step-by-Step Explanation:

Add 9, 3, 212, 3, and 7. You get 234. You can't change 6k because the variable, so you end up with 6k+234.

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What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
telo118 [61]

Answer:

f(x)=-\frac{1}{8}(x-3)^2+3

Step-by-step explanation:

We want to find the equation of the parabola with a focus of (3,1) and directrix y=5.

Considering the directrix, the quadratic graph must open downwards.


The equation of this parabola is given by the formula,

(x-h)^2=4p(y-k), where (h,k) is the vertex of the parabola.


The axis of this parabola meets the directrix at (3,5).

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,


h=\frac{3+3}{2}=3 and k=\frac{5+1}{2}=3.


The equation of the parabola now becomes,


(x-3)^2=4p(y-3).


Also |p| is the distance between the vertex and the directrix.


|p|=2


This implies that p=-2\:or\:2.


Since the parabola turns downwards,


p=-2.



Our equation now becomes,


(x-3)^2=4(-2)(y-3).


(x-3)^2=-8(y-3).


We make y the subject to get,

y=-\frac{1}{8}(x-3)^2+3).


This is the same as

f(x)=-\frac{1}{8}(x-3)^2+3).









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How to find the surface area of a prism
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The formula is 2(wl+hl+hw) to calculate surface area fo a rectangular prism.

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