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aleksandr82 [10.1K]
2 years ago
13

What is the value of 7x2−6x when x = 4

Mathematics
1 answer:
Yanka [14]2 years ago
8 0
You replace x with 4 7•4•2-6•4= 32
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Fill in the blank.
gavmur [86]

Answer:

297 cubic centimeters

Step-by-step explanation:

volume is LWH

11*9*3 = 297

6 0
3 years ago
What values of x makes -6x =12 true<br>​
Licemer1 [7]

Answer:

<h3>=> —6x = 12</h3><h3>=> —x = 12/6</h3><h3>=> —x = 2</h3>

<h2>=> x = —2</h2>

Step-by-step explanation:

hope it's helpful :-)

8 0
2 years ago
Read 2 more answers
The hourly wages earned by 20 employees are shown in the first box and whisker plot below. The person earning $15 per hour quits
serg [7]

I added the plots in the attachments.

<u><em>Answer:</em></u>

The mean will decrease

The median will remain the same

<u><em>Explanation:</em></u>

<u>1- checking the mean:</u>

<u>Mean of the salaries is calculated as follows:</u>

Mean = \frac{sum-of-salaries}{number-of-employees}

<u>Now, we can note that two parameters affect the mean, let's consider each:</u>

<u>a. Number of employees:</u>

We are given that one employee is replaced with another. This means that the number of employees did not change

<u>b. Sum of salaries:</u>

We are given that a person earning $15 left and the new person earns $7. This means that:

New sum of salaries = old sum of salaries - 15 + 7 = old sum of salaries - 8

This means that the sum of salaries decreased by 8

<u>Now, for the mean:</u>

We can conclude that since the numerator decreased while the denominator stayed the same, the mean will decrease

<u>2- checking the median:</u>

In the whisker plots, the median is represented by the vertical line inside the plot.

<u>In the first plot,</u> we can note that the vertical line is nearly half the distance between 9 and 10. This means that, for the first plot, the median is approximately 9.5

<u>In the second plot,</u> the place of the median is unchanged. It is still approximately midway between 9 and 10 which means that the median in the second plot is approximately 9.5

Therefore, the median of the data remains unchanged.

Hope this helps :)

5 0
3 years ago
Read 2 more answers
1. Write the slope-intercept form of the equation that passes through the point (0, 1) and is parallel to the line y = 3x - 5
gregori [183]

Answer:

y = 3x + 1

Step-by-step explanation:

If two lines are parallel to each other, they have the same slope.

The first line is Y = 3X - 5. Its slope is 3. A line parallel to this one will also have a slope of 3.

Plug this value (3) into your standard point-slope equation of y = mx + b.

y = 3x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (0, 1). Plug in the x and y values into the x and y of the standard equation.

1 = 3(0) + b

To find b, multiply the slope and the input of x (0)

1 = 0 + b

Now, add 0 to both sides to isolate b.

1 = b

Plug this into your standard equation.

y = 3x + 1

This equation is parallel to your given equation (y = 3x - 5) and contains point (0, 1)

Hope this helps!

3 0
3 years ago
Find dy/dx by implicit differentiation.
kow [346]

dy/dx by implicit differentiation is cos(πx)/sin(πy)

<h3>How to find dy/dx by implicit differentiation?</h3>

Since we have the equation

(sin(πx) + cos(πy)⁸ = 17, to find dy/dx, we differentiate implicitly.

So, [(sin(πx) + cos(πy)⁸ = 17]

d[(sin(πx) + cos(πy)⁸]/dx = d17/dx

d[(sin(πx) + cos(πy)⁸]/dx = 0

Let sin(πx) + cos(πy) = u

So, du⁸/dx = 0

du⁸/du × du/dx = 0

Since,

  • du⁸/du = 8u⁷ and
  • du/dx = d[sin(πx) + cos(πy)]/dx

= dsin(πx)/dx + dcos(πy)/dx

= dsin(πx)/dx + (dcos(πy)/dy × dy/dx)

= πcos(πx) - πsin(πy) × dy/dx

So, du⁸/dx = 0

du⁸/du × du/dx = 0

8u⁷ × [ πcos(πx) - πsin(πy) × dy/dx] = 0

8[(sin(πx) + cos(πy)]⁷ ×  (πcos(πx) - πsin(πy) × dy/dx) = 0

Since 8[(sin(πx) + cos(πy)]⁷ ≠ 0

(πcos(πx) - πsin(πy) × dy/dx) = 0

πcos(πx) = πsin(πy) × dy/dx

dy/dx = πcos(πx)/πsin(πy)

dy/dx = cos(πx)/sin(πy)

So, dy/dx by implicit differentiation is cos(πx)/sin(πy)

Learn more about implicit differentiation here:

brainly.com/question/25081524

#SPJ1

6 0
2 years ago
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