Answer: d) Prandtl number
Explanation: Prandtl number is basically defined as the ratio between the fluid's viscosity to the thermal conductivity.It doesn't have any sort of dimension. The fluids which are discovered with the small Prandtl numbers are considered as good fluids as they have a smooth rate of flow and as the number increases the fluid are not considered as reliable. Thus,option (d) is the correct option.
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Given that the correct question is
Write Python expressions using s1, s2, and s3 and operators + and * that evaluate to: (a) 'ant bat cod'
Answer:
s1 = 'ant'
s2 ='bat'
s3 ='cod'
#using string concatenation
s4 = s1 + ' ' + s2 + ' ' +s3
print(s4)
You sometimes service vehicles with rust damage. It's safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points. This is false.
<h3>What is rust?</h3>
Rust is an iron oxide, a typically reddish-brown oxide created when iron and oxygen react catalytically with moisture from the air or water. Iron(III) oxide-hydroxide and hydrous iron(III) oxides make up rust, which is often linked to the corrosion of refined iron.
Rusting is the chemical process that causes a red or orange coating to form on the surface of metals. Corrosion incorporates rusting. Steel and iron rust when they come into contact with oxygen and water, which are both necessary for rusting to take place.
It should be noted that when servicing vehicles with rust damage, It's not safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points. This can cause an accident.
Learn more about rust on:
brainly.com/question/1477535
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You sometimes service vehicles with rust damage. It's safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points.
True
False
Answer:
B) voltage at the sending end of the feeder = 2483.66 v
Explanation:
attached below is the the equivalent circuits and the remaining solution for option A
B) voltage = 2400 v
I =
= 20.83 A
calculate voltage at sending end ( Vs )
Vs = 2400 + 20.83 ∠ -cos^-1 (0.8) ( 0.75*2 + 0.5 + j 2 + j2 )
hence Vs = 2483.66 ∠ 0.961
therefore voltage at the sending end = 2483.66 v