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4 years ago

What precautions should you take to prevent injuries when dealing with heavy loads?

2 answers:

8 0

There are three quick tips like to estimate the amount of work to be done, correct posture for lifting the object and lowering the object.

Explanation

Most of the workers suffer from severe backache problems caused by lifting heavy loads leading.

This can be prevented of the workers follow three quick tips.

The first one is to estimate the amount of work to be done by the worker before committing for it like measure the distance you have to carry the heavy load, the size of the load and where the load can be kept easily for easy transfer.

The second one is we have to keep out back straight, lower our knees while carrying the heavy load to prevent injuries.

The third one is that while unloading the object, we have to maintain the same posture what we kept while loading it.

pychu [463]4 years ago

7 0

<u>Answer with explanation:</u>

When dealing with heavy loads, one needs to take certain precautions in order to avoid or prevent from injuries.

For instance, one should avoid lifting above the shoulder level which can end up pulling your muscle.

Also, you can either break the load in parts if possible or get some help for lifting heavy bulks.

Moreover, one should try to lift with the legs while keeping the back straight and not twisting it.

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At the coast on a summer day, the land is hotter than the ocean. Warm air over the land rises and is replaced by cooler air, cau

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B) The convection current will reverse direction, reversing the winds.

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3 years ago

Read 2 more answers

Air at atmospheric pressure and at 300K flows with a velocity of 1.5m/s over a flat plate. The transition from laminar to turbul

Savatey [412]

Answer:3.47 m

Explanation:

Given

Temperature(T)=300 K

velocity(v)=1.5 m/s

At 300 K

$\mu =1.846 \times 10^{-5} Pa-s$

$\rho =1.77 kg/m^3$

And reynold's number is given by

$Re.=\frac{\rho v\time x}{\mu }$

$5\times 10^5=\frac{1.77\times 1.5\times x}{1.846\times 10^{-5}}$

$x=\frac{5\times 10^5\times 1.846\times 10^{-5}}{1.77\times 1.5}$

x=3.47 m

5 0

4 years ago

Consider an aircraft powered by a turbojet engine that has a pressure ratio of 9. The aircraft is stationary on the ground, held

77julia77 [94]

Answer:

The break force that must be applied to hold the plane stationary is 12597.4 N

Explanation:

p₁ = p₂, T₁ = T₂

$\dfrac{T_{2}}{T_{1}} = \left (\dfrac{P_{2}}{P_{1}} \right )^{\frac{K-1}{k} }$

${T_{2}}{} = T_{1} \times \left (\dfrac{P_{2}}{P_{1}} \right )^{\frac{K-1}{k} } = 280.15 \times \left (9 \right )^{\frac{1.333-1}{1.333} } = 485.03\ K$

The heat supplied = $\dot {m}_f$ × Heating value of jet fuel

The heat supplied = 0.5 kg/s × 42,700 kJ/kg = 21,350 kJ/s

The heat supplied = $\dot m$ · $c_p(T_3 - T_2)$

$\dot m$ = 20 kg/s

The heat supplied = 20* $c_p(T_3 - T_2)$ = 21,350 kJ/s

$c_p$ = 1.15 kJ/kg

T₃ = 21,350/(1.15*20) + 485.03 = 1413.3 K

p₂ = p₁ × p₂/p₁ = 95×9 = 855 kPa

p₃ = p₂ = 855 kPa

T₃ - T₄ = T₂ - T₁ = 485.03 - 280.15 = 204.88 K

T₄ = 1413.3 - 204.88 = 1208.42 K

$\dfrac{T_5}{T_4} = \dfrac{2}{1.333 + 1}$

T₅ = 1208.42*(2/2.333) = 1035.94 K

$C_j = \sqrt{\gamma \times R \times T_5}$ = √(1.333*287.3*1035.94) = 629.87 m/s

The total thrust = $\dot m$ × $C_j$ = 20*629.87 = 12597.4 N

Therefore;

The break force that must be applied to hold the plane stationary = 12597.4 N.

5 0

3 years ago

For a LED diode that has a= 632 nm, then the A1 is equal to:

alexgriva [62]

Answer:

1.693242

Explanation:

The colors in the Light emitting diodes have been identified by wavelength which is measured in nano-meters. Wavelength is a function of LED chip material. The LED diode which has a = 632 then A1 will be 1.63242, this is calculated by 1 / 632. Wavelength are important for human eye sensitivity. The colors emitted from the LED will depend on the semiconductor material.

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3 years ago

If he wants to keep the height the same, what could the other dimensions be for him to get the volume he wants?

Fiesta28 [93]

tbm queria saber essa pergunta

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3 years ago