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miv72 [106K]
4 years ago
6

What precautions should you take to prevent injuries when dealing with heavy loads?

Engineering
2 answers:
GrogVix [38]4 years ago
8 0

There are three quick tips like to estimate the amount of work to be done, correct posture for lifting the object and lowering the object.

Explanation

Most of the workers suffer from severe backache problems caused by lifting heavy loads leading.

This can be prevented of the workers follow three quick tips.

The first one is to estimate the amount of work to be done by the worker before committing for it like measure the distance you have to carry the heavy load, the size of the load and where the load can be kept easily for easy transfer.

The second one is we have to keep out back straight, lower our knees while carrying the heavy load to prevent injuries.

The third one is that while unloading the object, we have to maintain the same posture what we kept while loading it.

pychu [463]4 years ago
7 0

<u>Answer with explanation:</u>

When dealing with heavy loads, one needs to take certain precautions in order to avoid or prevent from injuries.

For instance, one should avoid lifting above the shoulder level which can end up pulling your muscle.

Also, you can either break the load in parts if possible or get some help for lifting heavy bulks.

Moreover, one should try to lift with the legs while keeping the back straight and not twisting it.

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______number can be used to describe the relative growth of the hydraulic boundary layer and the thermal boundary layer. a) Reyn
weqwewe [10]

Answer: d) Prandtl number

Explanation: Prandtl number is basically defined as the ratio between the fluid's viscosity to the thermal conductivity.It doesn't have any sort of dimension. The fluids which are discovered with the small Prandtl numbers are considered as good fluids as they have a smooth rate of flow and as the number increases the fluid are not considered as reliable. Thus,option (d) is the correct option.

3 0
4 years ago
Ayuda!<br> es para mañana
ExtremeBDS [4]
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8 0
3 years ago
Write Python expressions using s1, s2, and s3 and operators and * that evaluate to: (a) 'ant bat cod'
jenyasd209 [6]

Given that the correct question is

Write Python expressions using s1, s2, and s3 and operators + and * that evaluate to: (a) 'ant bat cod'

Answer:

s1 = 'ant'

s2 ='bat'

s3 ='cod'

#using string concatenation

s4 = s1 + ' ' + s2 +  ' ' +s3

print(s4)

5 0
3 years ago
7. You sometimes service vehicles with rust damage. It's safe to lift them on a two-post,
solong [7]

You sometimes service vehicles with rust damage. It's safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points. This is false.

<h3>What is rust?</h3>

Rust is an iron oxide, a typically reddish-brown oxide created when iron and oxygen react catalytically with moisture from the air or water. Iron(III) oxide-hydroxide and hydrous iron(III) oxides make up rust, which is often linked to the corrosion of refined iron.

Rusting is the chemical process that causes a red or orange coating to form on the surface of metals. Corrosion incorporates rusting. Steel and iron rust when they come into contact with oxygen and water, which are both necessary for rusting to take place.

It should be noted that when servicing vehicles with rust damage, It's not safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points. This can cause an accident.

Learn more about rust on:

brainly.com/question/1477535

#SPJ1

You sometimes service vehicles with rust damage. It's safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points.

True

False

8 0
2 years ago
A single phase, 50-KVA, 2400-240-volt, 60 Hz distribution transformer has the following parameters: •
never [62]

Answer:

B) voltage at the sending end of the feeder = 2483.66 v

Explanation:

attached below is the the equivalent circuits and the remaining solution  for option A

B) voltage = 2400 v

   I  = \frac{50*10^3}{2400}  =  20.83 A

calculate voltage at sending end ( Vs )

Vs = 2400 +  20.83 ∠ -cos^-1 (0.8) ( 0.75*2 + 0.5 + j 2 + j2 )

hence Vs = 2483.66 ∠ 0.961

therefore voltage at the sending end = 2483.66 v

8 0
4 years ago
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