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Marat540 [252]
2 years ago
11

What is the importance of the causal link in work accidents?

Engineering
1 answer:
Elza [17]2 years ago
3 0

Causal link is very important to know the correlation between a cause and an outcome of a workplace accident which is useful for social insurance cover.

<h3>Understanding work accidents?</h3>

In work accidents, there is the need for evaluation criteria and injury determination. Now, this is where causal link comes in because we'll need to know whether the damage is a permanent disability or not.

Now, causal link is important because it helps us to know the correlation between a cause and an outcome of a workplace accident and whether it was intentional or caused by other factors. This is very important because of social insurance cover.

Read more about Work Accidents at; brainly.com/question/17583177

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Find the current Lx in the figure
AleksandrR [38]

Explanation:

\frac{1}{8}  +  \frac{1}{2}   \\ 1.6 + 1.4 = 3 \\  \frac{1}{3}  +  \frac{1}{9}   \\ 2.25 + 2 = 4.25 \: ohm

R total = 4.25 ohm

I total = Vt/Rt

I total= 17/4.25= 4 A

Ix= 600 mA

\frac{9}{9 + 3}  \times 4 = 3\\   \frac{2}{2 + 8} \times 3 = 0.6a \\  = 0.6 \: milli \: amper

6 0
3 years ago
Select all that apply: Contaminated sharps should<br><br> not be<br><br> ----
PIT_PIT [208]

Answer:

Contaminated sharps should not be bent, recapped or removed.

Explanation:

Contaminated sharps are defined as "any contaminated object that can penetrate the skin including, but not limited to, needles, scalpels, broken glass, broken capillary tubes and exposed ends of dental wires".

4 0
3 years ago
The given family of functions is the general solution of the differential equation on the indicated interval.Find a member of th
Alja [10]

Answer:

Explanation:

y'''+y=0---(i)

General solution

y=c_1e^o^x+c_2\cos x +c_3 \sin x\\\\\Rightarrow y=c_1+c_2 \cos x+c_3 \sin x---(ii)\\\\y(\pi)=0\\\\\Rightarrow 0=c_1+c_2\cos (\pi)+c_3\sin (\pi)\\\\\Rightarrow c_1-c_2=0\\\\c_1=c_2---(iii)

y'=-c_2\cos x+c_3\cosx\\\\y'(\pi)=2\\\\\Rightarrow2=-c_2\sin(\pi)+c_3\cos(\pi)\\\\\Rightarrow-c_2(0)+c_3(-1)=2\\\\\Rightarrow c_3=-2\\\\y''-c_2\cos x -c_3\sin x\\\\y''(\pi)=-1\\\\\Rightarrow-1=-c_2 \cos (\pi)=c_3\sin(\pi)\\\\\Rightarrow-1=c_2-0\\\\\Rightarrow c_2=-1

in equation (iii)

c_1=c_2=-1

Therefore,

\large\boxed{y=-1-\cos x-2\sin x}

5 0
3 years ago
Energy transfer in mechanical systems: During steady-state operation, a mechanical gearbox receives 70 KW of input power through
Degger [83]

Answer:

Heat transfer rate(Q)= 1.197kW

Power output(W)=68.803kW

3 0
3 years ago
Do not answer pls thank you
astra-53 [7]

The answer is answered! Explanation:

4 0
3 years ago
Read 2 more answers
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