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Elden [556K]
3 years ago
12

The giraffe is 15 feet tall. she is 2 1/2 times as tall as the elephant. how tall is the elephant?

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
5 0
The elephant is 6 feet tall. 15 divided by 2 1/2 is 6. To check multiply 6 and 2 1/2 you get 15. So the elephant is 6 feet tall. 
salantis [7]3 years ago
3 0
The giraffe is about 5 feet tall
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Which could be the dimensions of a rectangular prism to service area is less than 160 ft.² check all that apply
raketka [301]

Area of rectangular prism is given by:

A=2(wl+hl+lw)

where w=width h=height, l=length

checking for given options

1. 8 ft, by 4ft by 3ft

Area = 136 square feet

5. 3 feet by 5 feet by 7 feet

Area =142 square feet

so our first and last option matches the requirement of area less than 160 square feet.

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3 years ago
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Please answer look at pitot
klio [65]

Answer:

z = 7

Step-by-step explanation:

Based on the midsegment theorem of a triangle, the length of the midsegment of the triangle (z) = ½ of the length of the 3rd side of the triangle (14)

Thus:

z = ½(14)

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3 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

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Bond [772]

Answer:

AB = 9/2 cm

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x * (x-4) = x^2 -4x

The area of  the big rectangle

The height is 2x +x  and the width is x-2

(2x+x) * (x-2)

(3x) * (x-2)

3x^2 -6x

Add the areas together

x^2 -4x + 3x^2 -6x

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This is equal to 36

4x^2 -10x=36

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4x^2 -10x -36=36-36

4x^2 -10x-36=0

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2x^2 -5x -18=0

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Using the zero product property

x+2=0  2x-9=0

x = -2   2x =9

x = -2   x = 9/2

Since we cant have a negative length

x = 9/2

AB = 9/2 cm

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3 years ago
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alisha [4.7K]

Answer:

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Step-by-step explanation:

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Mr. Drew needs 68 feet of wood for the sides of the sandbox.

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