I think you meant to say
(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:
Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:
Do you have a picture? i can help if you have one
<u>Answer:</u>
0.45m + 33
<u>Step-by-step explanation:</u>
We are instructed to multiply the number the number of minutes Mr. Frotout spent on long distance calls by 0.45 the long distance rate then add 33 the flat monthly charge.
Assuming the number of long minutes spent on long distance calls by Mr. Frotout to be 
, we can express the given situation as follows:
Answer:
Answer is 0.1
Step-by-step explanation:
You might have rounded to the nearest hundredth instead of tenth, remember tenth is the first decimal, then hundredth, thousands, etc.
