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Kisachek [45]
1 year ago
8

I need to find side x of this 30 60 90 triangle i think with special right triangle methods

Mathematics
1 answer:
zvonat [6]1 year ago
4 0

This is a 30-60-90 triangle and we can apply rules to easily identify the hypotenuse of this triangle, which is denoted by <em>x</em>.

The length of the longer side of the triangle is given in the problem. To solve the hypotenuse of this triangle, let's solve first for the length of the shorter side of the triangle.

The shorter side can be solved by just dividing the length of the longer side by the square root of 3. Hence, we have

short=\frac{4}{\sqrt[]{3}}

Since we already have the values for the length of the shorter side and longer side, we can solve for the hypotenuse using the Pythagorean theorem.

\begin{gathered} c=\sqrt[]{a^2+b^2} \\ c=\sqrt[]{4^2+(\frac{4}{\sqrt[]{3}})^2} \\ c=\sqrt[]{16+\frac{16}{3}} \\ c=\sqrt[]{\frac{64}{3}} \\ c=\frac{8}{\sqrt[]{3}}\cdot\frac{\sqrt[]{3}}{\sqrt[]{3}} \\ c=\frac{8\sqrt[]{3}}{3} \end{gathered}

Hence, the value of hypotenuse for this right triangle is

x=\frac{8\sqrt[]{3}}{3}

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Step-by-step explanation:

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R(-1,-3), S(4,4), T(8,-1)<br><br><br> PLZ HELP ME
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9514 1404 393

Answer:

  see attachments

Step-by-step explanation:

The side lengths are found using the distance formula.

  d = √((x2-x1)^2 +(y2-y1)^2)

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__

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In every case here, the computed middle side is shorter than the actual middle-length side, so all of the triangles are acute triangles. (The one of problem 39 is isosceles, since two sides are the same length. The others are scalene.)

__

The triangles are graphed in the second attachment.

  problem 38: RST

  problem 39: ABC

  problem 40: DEF

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