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3 years ago

The function f(x) = (x-4)(x - 2) is shown below. What is true about the domain and range of the function?

Mathematics

1 answer:

8_murik_8 [283]3 years ago

8 0

The answer is B The domain is all real numbers such that ...

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3 years ago

Which equation is the inverse of 2(x - 2)2 = 8(7 + y)?

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Answer:

The inverse of $2(x - 2)^2 = 8(7 + y)$ is $y=\sqrt{(4x+28)}+2$

Step-by-step explanation:

Given equation : $2(x - 2)^2 = 8(7 + y)$

$\Rightarrow \frac{2(x-2)^2}{8}=7+y\\\Rightarrow \frac{2(x-2)^2}{8}-7=y$

Replace x with y and y with x

So, $\Rightarrow \frac{2(y-2)^2}{8}-7=x\\\Rightarrow \frac{2(y-2)^2}{8}=x+7\\\Rightarrow 2(y-2)^2=8(x+7)\\\Rightarrow (y-2)^2=4(x+7)\\\Rightarrow (y-2)=\sqrt{4(x+7)}\\\Rightarrow y=\sqrt{4(x+7)}+2\\\Rightarrow y=\sqrt{4x+28)}+2$

So, Option C is correct

Hence The inverse of $2(x - 2)^2 = 8(7 + y)$ is $y=\sqrt{(4x+28)}+2$

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3 years ago

3.) Simplify the expression.

Bogdan [553]

Answer:

Option C) -cosu is correct

Therefore the simplified expression is $cos(u+\pi)=-cosu$

Step-by-step explanation:

Given expression is $cos(u+\pi)$

To find the value of the given expression :

By using the formula $cos(A+B)=cosAcosB-sinAsinB$

Substitute A=u and $B=\pi$ in the above formula we get

$cos(u+\pi)=cosucos\pi-sinusin\pi$

$=cosu(-1)-sinu(0)$ ( here $cos\pi=-1$ and $sin\pi=0$ )

$=-cosu-0$

$=-cosu$

$cos(u+\pi)=-cosu$

Therefore option C) -cosu is correct

Therefore the simplified expression is $cos(u+\pi)=-cosu$

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