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9966 [12]
3 years ago
7

What is 348,000,000,000,000 estimated as the product of a single digit and a power of 10?

Mathematics
1 answer:
levacccp [35]3 years ago
3 0
The answer should be 3.48 X 10^18
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TIME REMAINING
mihalych1998 [28]

Answer:

The sum is 10s^2t-5st^2.  With two separate sections, it is a binomial, and since the sum of the powers of the variables is 2+1=3, it has a degree of 3.

4 0
2 years ago
Which two numbers add up to 10 and multiply to -24? can you help me with this?
vesna_86 [32]

Answer:

12, and -2

Step-by-step explanation:

12 + (-2) = 10

12 * (-2) = -24

6 0
2 years ago
How many 2/3 ounce portions of chocolate can Anna get from the 42/3 ounces of chocolate she bought at Union Market?
Lelechka [254]
She can get 21 portions. Since 2/3 and 42/3 already share the same denominator, all you need to do is divide 42 by 2 to get 21.
6 0
3 years ago
Which point is on the graph of the function y=3x+2<br>A.(1,5)<br>B.(2,3)<br>C.(3,2)<br>D.(5,1)​
evablogger [386]

Answer:

fyi links that are posted are fake

Step-by-step explanation:

4 0
3 years ago
The sum of 5 times a larger number and twice a smaller is 5. The difference of 4 times the larger and the smaller number is 4. F
Gemiola [76]

Answer:

1 and 0

Step-by-step explanation:

Let's call the smaller number x and the larger number y.

This means 5y+2x=5.

Also, 4y-x=4.

This is a system of equations. There are two main ways two solve this.

Method 1: Substitution

5y+2x=5

4y-x=4

Solve for one of the variables, then substitute it back into one of the equations to solve for the other variable.

I will take 4y-x=4 and solve for x.

4y=4+x

x=4y-4

Then substitute for x in the other equation and solve for y.

5y+2x=5

5y+2(4y-4)=5

5y+8y-8=5

13y=13

y=1

Now we can go back to our equation for x and substitute for y.

x=4y-4

x=4(1)-4=0

y, the larger number, is 1 and

x, the smaller number, is 0

Method 2: Elimination

5y+2x=5

4y-x=4

Change the equations so that the coefficient of one of the variables in an equation is opposite the one in the other equation. Then add the equations and solve for each variable.

If I multiply both sides of the second equation, 4y-x=4, by 2, the coefficient of x will become -2. In the first equation, the coefficient is 2, so they will become opposites.

4y-x=4

becomes

8y-2x=8

Now we have 5y+2x=5 and 8y-2x=8.

Add the sides of both equations to cancel the x values.

5y+2x+8y-2x=5+8

13y=13

y=1

like last time, we can substitute for y in any of the original equations to get x.

5y+2x=5

5(1)+2x=5

5+2x=5

2x=0

x=0

y, the larger number, is 1 and

x, the smaller number, is 0

6 0
2 years ago
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