Answer:
We do not have any problem to solve?
Step-by-step explanation:
Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
Answer:
B
Step-by-step explanation:
Answer with Step-by-step explanation:
We are given that
We have to explain that why the function is discontinuous at x=2
We know that if function is continuous at x=a then LHL=RHL=f(a).
LHL=Left hand limit when x <2
Substitute x=2-h
where h is small positive value >0
Right hand limit =RHL when x> 2
Substitute
x=2+h
LHL=RHL=
f(2)=1
Hence, function is discontinuous at x=2
Answer:
there are 150 in a twinkie and 300 in a cupcake
Step-by-step explanation:
3 x 150 = 450 then 150 x 2 = 300