9514 1404 393
Answer:
4
Step-by-step explanation:
The terms are separated by addition/subtraction symbols. There are 4 terms.
With parentheses around each term, you have ...
(9) + (14d) + (5w) + (7) . . . . 4 terms
_____
The two constant terms can be combined to give an expression with 3 terms:
14d +5w +16
The answer is X=4.
It is both parallel to x=-3 and passes through (4,2)
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
Answer:
(a)
Step-by-step explanation:
Given
4x - 1 = x ( subtract x from both sides )
3x - 1 = 0 ( add 1 to both sides )
3x = 1 ( multiply both sides by 10 )
30x = 10 → (a)
