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3 years ago

I’ve been having trouble with this question as I haven’t learnt it yet.

Mathematics

1 answer:

ELEN [110]3 years ago

8 0

R = $\frac{18}{5}$ = 3.6 and A = 2

given that R is inversely proportional to A, then

R = $\frac{k}{A}$ ← k is the constant of variation

To find k use the condition R = 12 when A = 1.5

k = RA = 12 × 1.5 = 18

the equation is therefore

R = $\frac{18}{A}$

when A = 5, then

R = $\frac{18}{5}$ = 3.6

when R = 9, then

9 = $\frac{18}{A}$ ( multiply both sides by A )

9A = 18 ( divide both sides by 9 )

A = 2

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Convert 96 ounces into pounds and explain how you determined the answer

stiks02 [169]

Hi there.

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3 years ago

Chapter 2 review / test 4th grade

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4 years ago

A movie rental club charges a one time fee of $25 to join and $2 for every movie rented which equation could represent how much

tia_tia [17]

Answer:

The correct answer option is B. c = 25 + 2m.

Step-by-step explanation:

We are given that a movie rental club charges a one time fee of $25 to join and $2 for every movie rented.

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7 0

3 years ago

Let R be the region bounded by

loris [4]

a. The area of $R$ is given by the integral

$\displaystyle \int_1^2 (x + 6) - 7\sin\left(\dfrac{\pi x}2\right) \, dx + \int_2^{22/7} (x+6) - 7(x-2)^2 \, dx \approx 9.36$

b. Use the shell method. Revolving $R$ about the $x$ -axis generates shells with height $h=x+6-7\sin\left(\frac{\pi x}2\right)$ when $1\le x\le 2$ , and $h=x+6-7(x-2)^2$ when $2\le x\le\frac{22}7$ . With radius $r=x$ , each shell of thickness $\Delta x$ contributes a volume of $2\pi r h \Delta x$ , so that as the number of shells gets larger and their thickness gets smaller, the total sum of their volumes converges to the definite integral

$\displaystyle 2\pi \int_1^2 x \left((x + 6) - 7\sin\left(\dfrac{\pi x}2\right)\right) \, dx + 2\pi \int_2^{22/7} x\left((x+6) - 7(x-2)^2\right) \, dx \approx 129.56$

c. Use the washer method. Revolving $R$ about the $y$ -axis generates washers with outer radius $r_{\rm out} = x+6$ , and inner radius $r_{\rm in}=7\sin\left(\frac{\pi x}2\right)$ if $1\le x\le2$ or $r_{\rm in} = 7(x-2)^2$ if $2\le x\le\frac{22}7$ . With thickness $\Delta x$ , each washer has volume $\pi (r_{\rm out}^2 - r_{\rm in}^2) \Delta x$ . As more and thinner washers get involved, the total volume converges to

$\displaystyle \pi \int_1^2 (x+6)^2 - \left(7\sin\left(\frac{\pi x}2\right)\right)^2 \, dx + \pi \int_2^{22/7} (x+6)^2 - \left(7(x-2)^2\right)^2 \, dx \approx 304.16$

d. The side length of each square cross section is $s=x+6 - 7\sin\left(\frac{\pi x}2\right)$ when $1\le x\le2$ , and $s=x+6-7(x-2)^2$ when $2\le x\le\frac{22}7$ . With thickness $\Delta x$ , each cross section contributes a volume of $s^2 \Delta x$ . More and thinner sections lead to a total volume of

$\displaystyle \int_1^2 \left(x+6-7\sin\left(\frac{\pi x}2\right)\right)^2 \, dx + \int_2^{22/7} \left(x+6-7(x-2)^2\right) ^2\, dx \approx 56.70$

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2 years ago

What is the sum of 1/12 plus 3/8 in a fraction? A.1/6 B.1/5 C.11/48 D.11/24

Nuetrik [128]

D.11/24
1/12=2/24
3/8=9/24
2/24+9/24=11/24

6 0

3 years ago

Read 2 more answers