Step 1
Find the area of one equilateral triangle
Applying the law of sines
in this problem
a=b=7 cm
C=60 degrees
so
cm²
Step 2
To calculate the area of the hexagon multiply the area of one equilateral triangle by 
![Area Hexagon=6*[49*\frac{\sqrt{3}}{4}] \\ Area Hexagon=73.5*\sqrt{3}](https://tex.z-dn.net/?f=%20Area%20Hexagon%3D6%2A%5B49%2A%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D%20%20%5C%5C%20Area%20Hexagon%3D73.5%2A%5Csqrt%7B3%7D%20%20)
cm²
therefore
the answer is the option
73.5 sqrt 3cm²
Pairs which is Adjacent side for quadrilateral MOLE is given below.
Step-by-step explanation:
Given:
Quadrilateral MOLE
Pair of adjacent sides of the quadrilateral.
Adjacent sides have one vertex common.
Option A: MO and LE
These sides does not have common vertex.
MO and LE are opposite sides in the quadrilateral MOLE.
It is not true.
Option B: EO and ME
In the quadrilateral, ME is not a side.
So it is not true.
Option C: LE and OL
In the quadrilateral, OL is not a side.
So it is not true.
Option D: ML and LE
These sides have common vertex L.
Therefore ML and LE are pair of adjacent sides.
It it true.
Hence ML and LE is a pair of adjacent side for quadrilateral MOLE.
Answer: wym and need more info like a pic or so
Step-by-step explanation:
I’m pretty sure it’s 18x +24
Down because it has a negative coefficient.
