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Ivenika [448]
3 years ago
12

Identify the equation of the parent function, y=x3, that is horizontally stretched by a factor of 1/5 and reflected over the y-a

xis.

Mathematics
2 answers:
sdas [7]3 years ago
5 0
The answer is y= (1/5x)^3
The answer is D
Rama09 [41]3 years ago
4 0

Answer:

The equation of the transformation is given as:

y=y=\dfrac{1}{5}(-x)^3=\dfrac{-x^3}{5}

Step-by-step explanation:

We are equation of the parent function as:

y=x^3

We have to find the expression for the transformed function which is formed by the horizontally stretched by a factor of 1/5 and reflected over the y-axis.

We know that horizontal stretch is denoted by:

y(ax) where a<1.

And the reflection over the y-axis transforms the function f(x) into:

f(x) to f(-x)

Hence, the transformation is given by:

y=y=\dfrac{1}{5}(-x)^3=\dfrac{-x^3}{5}

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