Hope pays $126 for 6 theater tickets. How much would 14 theater tickets cost?

2 answers:

8 0

126/6 = 21 If its 21$ per ticket then all that you have to do to finish the problem is multiply 21 by 14 which is 294. So for 14 tickets. The answer would be 294$

yan [13]4 years ago

3 0

$126 / 6 = 21

$21 = 1 theater ticket

$21 x 14 = $294

It would cost Hope $294 for 14 theater tickets

You might be interested in

Find the product. (4x - 3y) (2x + y)

antoniya [11.8K]

Answer:

8x^2 - 2xy + 3y^2

Step-by-step explanation:

Use the FOIL method

8x^2 + 4xy - 6xy + 3y^2

8x^2 - 2xy + 3y^2

7 0

4 years ago

If the discriminant is 22, then the roots of the quadratic equation are ________________.

Allisa [31]

Since the discriminant given has a value that is greater than zero, hence the roots of the quadratic equation are real and distinct.

<h3>Discriminant of a quadratic equation</h3>

Quadratic equation is an equation that has a leading degree of 2. The discriminant is used to determine the nature of the equation

If D > 0 , the roots of the quadratic equation are real and distinct.

If D < 0 , the roots of the quadratic equation are complex

Since the discriminant given has a value that is greater than zero, hence the roots of the quadratic equation are real and distinct.

Learn more on discriminant here: brainly.com/question/2507588

#SPJ1

4 0

2 years ago

PLEASE HURRY!! simplify completely show all work for full credit

Irina18 [472]

Answer:

$4x^{3}$

Step-by-step explanation:

Given:

$(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}$

Apply exponent rule of distribution:

$\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}$

Simplify the numerator:

$\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}$

Simplify the denominator:

$\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}$

Simplify:

$4x^{3}$

-> To explain this party since it is a bigger jump, $3^{\frac{1}{3}}x$ is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have $x^{3}$ leftover too.