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3241004551 [841]

3 years ago

11

Can u help with this?! One that solves best gets brainliest

1 answer:

lawyer [7]3 years ago

7 0

Answer:

2.) 3/8

3.) 3/8

4.) Couldn't read this one, too blurry

5.) 5/12

6.) 3/10

7.) 5/12

8.) 1/8

9.) 1/5

10.) 1/8

11.) 1/4

Step-by-step explanation:

So the thing about subtracting fractions is that you have to have the same denominator for both of them. (that's the number on the bottom.) So number 3 is 7/8 - 1/2. You're gonna wanna multiply 1/2 by four, for both the top and bottom number. This creates 4/8. Now you can subtract them! 7-4 = 3, and thus the answer is 3/8. You never, <em>ever</em> subtract the denominator: only the numerator.

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PLEASE HELP! Please I’m having a hard time with this I’ll be thankful

Arlecino [84]

Answer:

80 and 96

Step-by-step explanation:

80 and 96

7 0

3 years ago

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How many different 4-question geometry quizzes can a teacher make if there are 7 different problems to test on?.

stich3 [128]

Answer:

35 quizzes

Step-by-step explanation:

We need to determine how many ways we can choose 4 questions out of 7 to make the quizzes.

We do this by using the formula $\displaystyle nCr=\frac{n!}{r!(n-r)!}$ which describes the number of ways we can choose $r$ objects given $n$ possible choices. So, if $n=7$ and $r=4$ , then:

$_4C_7=\frac{7!}{4!(7-4)!}\\\\_4C_7=\frac{7*6*5*4!}{4!*3!}\\\\_4C_7=\frac{210}{6}\\\\_4C_7=35$

Hence, the teacher can make 35 different geometry quizzes.

3 0

2 years ago

654.29 divided by 19

AleksAgata [21]

Answer:

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Step-by-step explanation:

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3 years ago

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A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the total area of the pyramid.

Tanzania [10]

The total area of pyramid is 113.569 square units

The equation to find the total area of the pyramid is Total area = base area + lateral area.

<u>Solution:</u>

Given, A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6.

<em><u>The total area of pyramid is given by:</u></em>

$A=A_{b}+A_{l}$ ---- eqn 1

Where,

$A_{b} \text { is the base area and } A_{l} \text { is the lateral area }$

<em><u>The area of base is given as:</u></em>

$A_{b}=\frac{3 \sqrt{3}}{2} l^{2}$

Where "l" is the side of hexagon.

Substituting we get,

$\begin{array}{l}{A_{b}=\frac{3 \sqrt{3}}{2}(4)^{2}} \\\\ {=\frac{3 \sqrt{3}}{2} \times 16=3 \sqrt{3} \times 8} \\\\ {A_{b}=24 \sqrt{3}}\end{array}$

<em><u>The lateral area is given as:</u></em>

$A_{l}=3 b h$

Where,

b: base of the triangle

h: height of the triangle

Substituting we get,

$\begin{array}{l}{A_{l}=3 \times(4) \times(6)} \\\\ {A_{l}=72}\end{array}$

Plugging in the values we found in eqn 1 we get,

$A=24 \sqrt{3}+72$

A = 113.569 square units

<em><u>Summarizing the results:</u></em>

The total area of pyramid is 113.569 square units approximately

The equation used to find total area of pyramid is Total area = base area + lateral area.

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3 years ago

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Answer:

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