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3241004551 [841]
3 years ago
11

Can u help with this?! One that solves best gets brainliest

Mathematics
1 answer:
lawyer [7]3 years ago
7 0

Answer:

2.) 3/8

3.) 3/8

4.) Couldn't read this one, too blurry

5.) 5/12

6.) 3/10

7.) 5/12

8.) 1/8

9.) 1/5

10.) 1/8

11.) 1/4

Step-by-step explanation:

So the thing about subtracting fractions is that you have to have the same denominator for both of them. (that's the number on the bottom.) So number 3 is 7/8 - 1/2. You're gonna wanna multiply 1/2 by four, for both the top and bottom number. This creates 4/8. Now you can subtract them! 7-4 = 3, and thus the answer is 3/8. You never, <em>ever</em> subtract the denominator: only the numerator.

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(5x2 + 2x + 11) - (7 + 4x - 2x2)
storchak [24]
The answer is 7x^2 - 2x + 4, so answer D. 
6 0
3 years ago
Read 2 more answers
SOMEONE HELP ASAPPPP PLEASEEE,PLEASE EXPLAIN HOW U GOT YOUR ANSWER, I NEED AN EXPLANATION IN ORDER TO COMPLETE THIS! NO LINKS OR
kaheart [24]

Answer:

x = 5

Step-by-step explanation:

4x + 2y + z = 24

2x - 3y - z = 2

5x + y + 2z = 21

-----------------

Eliminate z

Add the 1st and 2nd eqn

4x + 2y + z = 24

2x - 3y - z = 2

----------------

6x - 1y = 26 eqn A

Multiply the 2nd eqn by 2, then add the 3rd.

4x - 6y -2z = 4

5x + y + 2z = 21

----------------

9x - 5y = 25 eqn B

---------------

Now you have 2 eqns in 2 unknowns, not 3.

Multiply eqn A by 5 and subtract eqn B.

30x - 5y = 130 eqn A times 5

9x - 5y = 25 eqn B

-------------

21x = 105

x = 5

4 0
3 years ago
Read 2 more answers
A child walks 3/10 of a mile in 1\5 hour. At this rate, how far will the child walk in 1 hour
defon

Answer:

1½ mile

Step-by-step explanation:

Given

3/10 mile = ⅕ hour

Required

Determine the distance in 1 hour

Since rate is constant, we have:

3/10 mile = ⅕ hour

Multiply both sides by 5

5 * 3/10 mile = ⅕ hour * 5

15/10 mile = 5/5 hour

3/2 mile = 1 hour

1½ mile = 1 hour

Hence,the child will walk 1½ mile in 1 hour

8 0
3 years ago
Vertex form is f(x)=a(x-p)^2 +q. How do i determine a?
slamgirl [31]
Y1 is the simplest parabola.  Its vertex is at (0,0) and it passes thru (2,4).  This is enough info to conclude that y1 = x^2.

y4, the lower red graph, is a bit more of a challenge.  We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).

Let's try this:  assume that the general equation for a parabola is 
y-k = a(x-h)^2, where (h,k) is the vertex.  Subst. the known values,

-3-(-4) = a(2-0)^2.  Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.

The equation of parabola y4 is   y+4 = (1/4)x^2

Or you could elim. the fraction and write the eqn as 4y+16=x^2, or

4y = x^2-16, or    y = (1/4)x - 4.  Take your pick!  Hope this helps you find "a" for the other parabolas.


8 0
3 years ago
Which statement about the value of x is true?
Anarel [89]
The best way to find the answer is to solve for x. To start you would add 38 and 39, getting 77, then subtract that from 180 to get the last angle in the triangle, 103. Finally, you would subtract 103 from 180, getting 77, to get x. The only thing you need to do now is to look at all of the answers and figure out which one makes sense for the answer you got. You know it can't be x<77 because it doesn't have the or equal to sign. You know it can't be x>103 because 77 is lower than 103. You know it can't be x<39 because 77 is greater than 39, so the answer has to be x > 38.
4 0
3 years ago
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