All categories

3 years ago

Find the product. (4x - 3y) (2x + y)

Mathematics

1 answer:

antoniya [11.8K]3 years ago

7 0

Answer:

8x^2 - 2xy + 3y^2

Step-by-step explanation:

Use the FOIL method

8x^2 + 4xy - 6xy + 3y^2

8x^2 - 2xy + 3y^2

You might be interested in

Pryce Company owns equipment that cost $65,000 when purchased on January 1, 2012. It has been depreciated using the straight-lin

ki77a [65]

Monthly depreciation is calculated as follows:
65,000 (Cost) – 5,000 (Salvage Value) ÷ 60 (5 years X 12 months per year) = 1,000 in depreciation per month.

a) Accumulated depreciation from 1/1/12 to 1/1/15 is 36,000 (12 months for 2012, 2013, & 2014).
Assuming that sale was a Cash sale, the journal entry would look like this:
1/1/15
Cash (DR) 31,000
Accumulated Depreciation (DR) 36,000
Equipment (CR) 65,000
Gain on Sale of Equipment (CR) 2,000

b) Accumulated depreciation from 1/1/12 to 5/1/15 is 40,000 (12 months for 2012, 2013, 2014, & 4 months for 2015).
Assuming that sale was a Cash sale, the journal entry would look like this:
5/1/15
Cash (DR) 31,000
Accumulated Depreciation (DR) 40,000
Equipment (CR) 65,000
Gain on Sale of Equipment (CR) 6,000

c) Accumulated depreciation from 1/1/12 to 1/1/15 is 36,000 (12 months for 2012, 2013, & 2014).
Assuming that sale was a Cash sale, the journal entry would look like this:
1/1/15
Cash (DR) 11,000
Accumulated Depreciation (DR) 36,000
Loss on Sale of Equipment (DR) 18,000
Equipment (CR) 65,000

d) Accumulated depreciation from 1/1/12 to 10/1/15 is 45,000 (12 months for 2012, 2013, 2014, & 9 months for 2015).
Assuming that sale was a Cash sale, the journal entry would look like this:
10/1/15
Cash (DR) 11,000
Accumulated Depreciation (DR) 45,000
Loss on Sale of Equipment (DR) 9,000
Equipment (CR) 65,000

Not my answers, but I hope this will help you. :)

7 0

3 years ago

What is the decimal for 1/8

Andrews [41]

0.125 but 0.13 if it asks you to round

3 0

3 years ago

Read 2 more answers

Can u please do 1,2

Sidana [21]

1) First, you have to add all the 3 pieces of wood
10+7.5+12= 29.5 ft.
Second, you have to add the pieces that he has used
5.2 +6.2= 11.4 ft
Third, you have subtract the used wood from the whole wood to get how many feet he didn't use
29.5 - 11.4=18.1 ft.
I hope it helped. But, sorry don't know how to do number 2.

7 0

2 years ago

. Paige can complete a landscaping job in

Lapatulllka [165]

Maybe less than 4hrs since there’s two working together and since malia can complete less than Paige

5 0

2 years ago

Item 7

Mariulka [41]

Answer:

$A = 74.7^\circ$

$B = 42.5^\circ$

$C = 62.8^\circ$

Step-by-step explanation:

Given

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

For AB

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$d = \sqrt{(-1 - 2)^2 + (2 - 8)^2$

$d = \sqrt{(-3)^2 + (-6)^2$

$d = \sqrt{45$

So:

$AB = \sqrt{45$

For BC

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

$BC = \sqrt{(2 - 4)^2 + (8 - 1)^2$

$BC = \sqrt{(-2)^2 + (7)^2$

$BC = \sqrt{53$

For AC

$A = (-1,2) \to (x_1,y_1)$

$C = (4,1) \to (x_3,y_3)$

$AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2$

$AC = \sqrt{(-5)^2 + (1)^2$

$AC = \sqrt{26$

So, we have:

$AB = \sqrt{45$

$BC = \sqrt{53$

$AC = \sqrt{26$

By representation

$AB \to c$

$BC \to a$

$AC \to b$

So, we have:

$a = \sqrt{53$

$b = \sqrt{26$

$c = \sqrt{45$

By cosine laws, the angles are calculated using:

$a^2 = b^2 + c^2 -2bc \cos A$

$b^2 = a^2 + c^2 -2ac \cos B$

$c^2 = a^2 + b^2 -2ab\ cos C$

$a^2 = b^2 + c^2 -2bc \cos A$

$(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A$

$53 = 26 +45 - 2 * 34.21 * \cos A$

$53 = 26 +45 - 68.42 * \cos A$

Collect like terms

$53 - 26 -45 = - 68.42 * \cos A$

$-18 = - 68.42 * \cos A$

Solve for $\cos A$

$\cos A =\frac{-18}{-68.42}$

$\cos A =0.2631$

Take arc cos of both sides

$A =\cos^{-1}(0.2631)$

$A = 74.7^\circ$

$b^2 = a^2 + c^2 -2ac \cos B$

$(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B$

$26 = 53 +45 -97.67 * \cos B$

Collect like terms

$26 - 53 -45= -97.67 * \cos B$

$-72= -97.67 * \cos B$

Solve for $\cos B$

$\cos B = \frac{-72}{-97.67}$

$\cos B = 0.7372$

Take arc cos of both sides

$B = \cos^{-1}(0.7372)$

$B = 42.5^\circ$

For the third angle, we use:

$A + B + C = 180$ --- angles in a triangle

Make C the subject

$C = 180 - A -B$

$C = 180 - 74.7 -42.5$

$C = 62.8^\circ$

8 0

2 years ago