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Thepotemich [5.8K]
3 years ago
6

By definition, the determinant equals ad - bc. What is the value of when x = -2 and y = 3? I NEED HELP PLEASE

Mathematics
1 answer:
sergiy2304 [10]3 years ago
4 0

Answer:

<h3>B. -84</h3>

Step-by-step explanation:

Taking the determinant of the matrices we will have;

= 4x(5y) - 2x(3y)

= 20xy - 6xy

= 14xy

Given x = -2 and y = 3

Determinant = 14(-2)(3)

Determinant = -28*3

Determinant = -84

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40 POINTS!!!! ANSWER CORRECTLY PLZ
Grace [21]

Answer:

5. ○ \displaystyle \frac{25}{48}

4. ○ \displaystyle \frac{25}{46}

3. ○ \displaystyle \frac{31}{100}

2. ○ \displaystyle \frac{3}{4}

1. ○ \displaystyle \frac{27}{50}

Step-by-step explanation:

5. \displaystyle \frac{25}{23 + 25} = \frac{25}{48}

4. \displaystyle \frac{25}{46} = \frac{25}{21 + 25}

3. \displaystyle Flat-out\:given\:to\:you

2. \displaystyle \frac{21 + 23 + 31}{100} = \frac{75}{100} = \frac{3}{4}

1. \displaystyle \frac{31 + 23}{100} = \frac{54}{100} = \frac{27}{50}

I am joyous to assist you anytime.

7 0
3 years ago
Question 7 Daurie rides on her motorcycle for 252 miles on 6 gallons of gas. At this rate, how far will she get on 2 gallons of
SIZIF [17.4K]

Answer: 0.0476 miles

Step-by-step explanation:

Daurie rides on her motorcycle for 252 miles on 6 gallons of gas. We will determine the unit rate in gallons. It means the number of miles that her motorcycle on one gallon of gas

Distance travelled on one gallon of gas would be 6/252 = 0.0238 miles

At this rate of 0.0238 miles per one gallon of gas, the distance travelled on 2 gallons of gas would be

2 × 0.0238 = 0.0476 miles

6 0
3 years ago
If anyone knows how to report PERSON on brainly please me bc someone is h0m0ph0bc saying lgbtq should go die, keeps using the n
Charra [1.4K]

Step-by-step explanation:

Sadly, users cannot be reported but any content by that person can be reported by pressing the little flag icon. If it doesn't stop after reporting the comments I suggest reaching out to Brainly by Email!

5 0
3 years ago
Please help me It’ll help a lot
Digiron [165]

Answer:

heyy

the answers "20"

Step-by-step explanation:

Okay using the x that we have we find 40 and plug that into the graph and we have 20 :p

7 0
3 years ago
A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

P(YX) =0.6 \times 0.01

P(YX) =0.006

The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
3 years ago
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