Well, from 2008 to 2010 is just 2 years, so let's say the initial amount is the 19300 from 2008, how many will it be in 2010?

$\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &19300\\
r=rate\to 20\%\to \frac{20}{100}\to &0.20\\
t=\textit{elapsed time}\to &2\\
\end{cases}
\\\\\\
A=19300(1+0.2)^2$

6 0

3 years ago

Adam is training a group of cyclists. Each cyclist completes a 10-kilometer time trial during training. Adam records the times,

nydimaria [60]

The histogram which shows the results of the time trial is option B

<h3>Histogram</h3>

Given data:

12:32, 12:46, 13:30, 15:03, 13:43, 13:46, 14:20, 14:29, 12:34, 14:43, 15:26, 16:02, 16:16, 14:38, 16:55, 17:10, 14:26, 17:21, 17:58, 13:30

Grouping of data,:

12:00 - 12:59 = 3

13:00 - 13:59 = 4

14:00 - 14:59 = 5

15:00 - 15:59 = 2

16:00 - 16:59 = 3

17:00 - 17:59 = 3

The frequency is represented on the y-axis(number of cyclist)
The time is represented on the x-axis

Learn more about histogram:

brainly.com/question/9388601

#SPJ1

7 0

1 year ago