2 years ago

Simplify i^12. a. 1 b. −1 c. −i d. i

1 answer:

4 0

I^12 = (i^4)^3 = 1^3 = 1

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vaieri [72.5K]

Answer:

see explanation

Step-by-step explanation:

Note the common difference d between consecutive terms of the sequence

8 - 6 = 10 - 8 = 2

This indicates that the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 6 and d = 2, thus

$a_{n}$ = 6 + 2(n - 1) = 6 + 2n - 2 = 2n + 4 ← explicit formula

Hence

$a_{130}$ = (2 × 130) + 4 = 260 + 4 = 264

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3 years ago