Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
<span>Because the town was built above sheer cliffs that were heavily defended by artillery.</span>
<em>Answer:</em>
<em>-24, 48, -96</em>
<em>Step-by-step explanation:</em>
<em>The number before multiplies by -2.</em>
<em>3*-2=-6</em>
<em>and so on. </em>
<em>Hope this helps. Have a nice day.</em>
Answer:
14,146 years
Step-by-step explanation:
The annual multiplier is (1 -0.0049%) = 0.999951. We want to find the number of times this needs to be multiplied to make the product 1/2.
0.5 = 0.999951^t
log(0.5) = t·log(0.999951)
log(0.5)/log(0.999951) = t ≈ 14,145.514
The half-life is about 14,146 years.
