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Elanso [62]
2 years ago
10

What is the 9th term of the geometric sequence 4, −20, 100, …?

Mathematics
2 answers:
aksik [14]2 years ago
8 0
1 = 4
2 = -20
3 = 100
4 = -500
5 = 2500
6 = - 12,500
7 = 62, 500
8 = - 312, 500
9 = 1,562,500

Hope this helped☺☺
blagie [28]2 years ago
4 0
4, -20, 100, -500, 2500, -12500, 62500, -312500, 1562500.
1,562,500 is your answer. 
I hope this helps!
(All the numbers were multiplied by -5 to get the answer.)
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Step-by-step explanation:

x : # of months that has gone by

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1. 39.95 + 0.10x > 0.24x

2. 39.95 > 0.24x - 0.10x

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y=3/8x-4
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5 0
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Which of these steps will eliminate a variable in this system?
PSYCHO15rus [73]
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3 0
3 years ago
Plssss help quick i need it for sum important
Vanyuwa [196]

(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

7 0
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