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bazaltina [42]
2 years ago
11

Can you please use my for gauth code GHD989​

Mathematics
1 answer:
viva [34]2 years ago
4 0

Answer:

what........???????............

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Find three consecutive numbers whose sum equals<br>999.​
mina [271]

Answer:

332, 333, 334

Step-by-step explanation:

First, we acknowledge that the equation that we need to solve will be "x+(x+1)+(x+2)=999" This is because x represents the smallest of three consecutive numbers whose sum is 999. Simplifying this equation will leave us with 3x+3=999 which is simplified further to 3x=996 and again simplified to x=332. X is the smallest number of the three.

4 0
2 years ago
Kamal bought a package of 2 oatmeal cookies. The total weight of the cookies was 1 ounce. How much did each cookie weigh?
worty [1.4K]

Answer: 0.5 oz is the weight of one cookie

Step-by-step explanation: If 2 cookies weight 1 oz then 1 cookie weights 0.5 oz.

4 0
3 years ago
Im B.O.R.E.D I NEED TO T.A.L.K
FromTheMoon [43]

Answer: hi thanks for the five

Step-by-step explanation:

5 0
3 years ago
A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th
umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, <em>p</em> = 0.09.

An item is defective irrespective of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

C=3X^{2}+X+2

Compute the expected cost of repair as follows:

E(C)=E(3X^{2}+X+2)

        =3E(X^{2})+E(X)+2

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.09\\=0.36

The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)

         =4\times 0.09\times 0.91\\=0.3276\\

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

V(X)=E(Y^{2})-(E(Y))^{2}

Then the formula of E(Y^{2}) is:

E(Y^{2})=V(X)+(E(Y))^{2}

Compute the value of E(Y^{2}) as follows:

E(Y^{2})=V(X)+(E(Y))^{2}

          =0.3276+(0.36)^{2}\\=0.4572

The expected repair cost is:

E(C)=3E(X^{2})+E(X)+2

         =(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73

Thus, the expected repair cost is $3.73.

4 0
3 years ago
What is the distance between points N and M?
Ira Lisetskai [31]

Answer:

B. 5.8

Step-by-step explanation:

When you do the Pythagorean theorem, you would set 5 as a and 3 as b.

Square both sides and add to get 34

You then take the square root of that to find c which would be 5.8

4 0
2 years ago
Read 2 more answers
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