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3 years ago

Please help me 7th grade math

Mathematics

2 answers:

Eddi Din [679]3 years ago

8 0

Answer:

1/8

Step-by-step explanation:

ohaa [14]3 years ago

5 0

Answer: 1/8

Step-by-step explanation: hoped this helped :))

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(PLEASE ANSWER + BRAINLIEST!!)

Licemer1 [7]

The answer is x=20. Hope this helps.

8 0

3 years ago

Defining congruent triangles

seropon [69]

Answer:

E -->R

D-->K

O-->O

Step-by-step explanation:

Assuming you are asking for congruent parts, correspondence is the part which corresponds and is also equal.

Here Angle E corresponds and is congruent to Angle R in these congruent triangles.

Angle D is congruent and corresponds to Angle K for these congruent triangles.

Angle O is equal to Angle O as they are vertical angles across a vertex.

5 0

3 years ago

I HAVE 5 MINUTES PLEASE HELP ! ( slope )

astraxan [27]

Answer:

1/2x+b=y

1/2*4+b=3

2+b=3

b=1

1/2x+1=y

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What's the curved line with the two parallel lines

VikaD [51]

It means that those 2 angles are the exact same length

7 0

3 years ago

I don’t understand this help please

Elodia [21]

Answer:

Step-by-step explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

(a·b)^c = a^c·b^c . . . . . . similar to the distributive property

 (a^b)^c = a^(b·c)

This reduces your expression to ...

$(2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}$

Now we can apply another two rules of exponents:

 (a^b)(a^c) = a^(b+c)

 1/a^b = a^-b

Using these, we have ...

$=2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9$

The value of the expression is 9.

3 0

3 years ago