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DerKrebs [107]
3 years ago
11

4-2(3+2) ² 2. Help me plz i need the help

Mathematics
2 answers:
strojnjashka [21]3 years ago
5 0

Answer:

-46 is your answer.

Step-by-step explanation:

=4-2(3+2)^2

=4-2(5)^2

=4-2(5✖️5)

=4-2(25)

Opening brackets to simplify

=4-50

=-46 is your answer.

Hope it will help you :)

Lynna [10]3 years ago
3 0

Answer:

-46

Step-by-step explanation:

4 - 2(3 + 2)^{2}  \\

PEDMAS

4 - 2(5)^{2}  \\ 4 - 2(25) \\ 4 - 50 \\  =  - 46

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Step-by-step explanation:

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kirill [66]

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Step-by-step explanation:

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\left[\begin{array}{cc}-3&9\\3&2\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}9\\13\end{array}\right]                  

Let A = \left[\begin{array}{cc}-3&9\\3&2\end{array}\right]    X =  \left[\begin{array}{c}x\\y\end{array}\right]  and B =    \left[\begin{array}{c}9\\13\end{array}\right]  

Then Mathematically AX= B

or X= A⁻¹ B

Where A⁻¹ = Adjacent A/ mod of A

Adjacent A =   \left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]    

Mod Of A= -6 - (27) = -33 which is not equal to zero

so Putting These values in the given formula

X= 1/-33    \left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]      \left[\begin{array}{c}9\\13\end{array}\right]  

Now Multiplying Rows and Columns

   \left[\begin{array}{c}x\\y\end{array}\right] = -1/33    \left[\begin{array}{cc}2*9+- 9*13\\-3*9 +- 3*13\end{array}\right]

Solving the Matrix we get

  \left[\begin{array}{c}x\\y\end{array}\right] = -1/33  \left[\begin{array}{cc}18-117\\-27-39\\\end{array}\right]

  \left[\begin{array}{c}x\\y\end{array}\right] = -1/33  \left[\begin{array}{cc}-99\\-66\end{array}\right]

From Here we find x= 99/33 or 3

and y = 66/33= 2

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