Answer: What is the question lol?
Step-by-step explanation:
Answer:
64 crates
Step-by-step explanation:
Smaller Cube Side Length = 2 1/2 feet, or, 2.5 feet
Larger Container (Cube) Side Length = 10 feet
We find volume of larger container and find volume of small crates. We divide the large volume by volume of each crate. This will give us number of crates we can fit.
Volume of Cube = x^3
Where x is the side length of the cube
Now,
Small Crate Volume = (2.5)^3 = 15.625 cubic feet
Large Container Volume = 10^3 = 1000 cubic feet
Number of crates that would fit = 1000/15.625 = 64
So, 64 crates will fit in the largest shipping container
Let
x--------> the border’s length
y--------> the border’s width
P--------> perimeter of the border
we know that
x=5+y------> equation 1
P=2*[x+y]-----> P=2x+2y
P <=180 ft
(2x+2y) <= 180-------> equation 2
substitute the equation 1 in equation 2
2*[5+y]+2y <= 180
10+2y+2y <= 180
4y <= 180-10
4y <=170
y <=42.5 ft
so
the maximum value of the width is 42.5 ft
for y=42.5 ft
x=42.5+5------> x=47.5 ft
the answer is
the width of the border is less than or equal to 42.5 ft
9514 1404 393
Answer:
AE = CE = 23; BE = DE = 20
Step-by-step explanation:
Put the values of the variables in their place and do the arithmetic.
AE = 2u+5 = 2(9) +5 = 23
BE = 6v-1 = 6(3.5) -1 = 20
CE = 3u-4 = 3(9) -4 = 23
DE = 8v-8 = 8(3.5) -8 = 20
The diagonals cross at their midpoints, so the quadrilateral is a parallelogram.
